Lagrange Multipliers
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- čas přidán 7. 11. 2019
- This calculus 3 video tutorial provides a basic introduction into lagrange multipliers. It explains how to find the maximum and minimum values of a function with 1 constraint and with 2 constraints.
Lines & Planes - Intersection: • How To Find The Point ...
Angle Between Two Planes:
• How To Find The Angle ...
Distance Between Point and Plane:
• How To Find The Distan...
Chain Rule - Partial Derivatives:
• Chain Rule With Partia...
Implicit Partial Differentiation:
• Implicit Differentiati...
________________________________
Directional Derivatives:
• How To Find The Direct...
Limits of Multivariable Functions:
• Limits of Multivariabl...
Double Integrals:
• Double Integrals
Local Extrema & Critical Points:
• Local Extrema, Critica...
Absolute Extrema - Max & Min:
• Absolute Maximum and M...
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Lagrange Multipliers:
• Lagrange Multipliers
Triple Integrals:
• Triple Integrals - Cal...
2nd Order - Differential Equations:
• Second Order Linear Di...
Undetermined Coefficients:
• Method of Undetermined...
Variation of Parameters:
• Variation of Parameter...
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Full-Length Videos and Worksheets:
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Good day Sir
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Please check the Calculus I, II and III lectures by Professor Leonard and Professor V.
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This is the most straightforward video I've seen on how to apply Lagrange multipliers. Just what I wanted: get right to the point without the theoretical math.
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Harjot Bhui perhaps I would in class, but that‘s a different setting then. I am convinced that Indians overuse that word and I don‘t seem to be the only one.
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This video is really helpful. Now I fully understand the Lagrange multipliers!
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I had a test last month on this and bombed a 12 point question about Lagrange multipliers lol. I'm in vector fields right now. I'm hoping he starts uploading quicker to catch up with my class
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@@brandontruong3110 Takes too long. Three hour lectures are hard to watch when you only have 7 hours left in a day after classes.
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@@brandontruong3110 calc 3? This is calc 2
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Good video. However, important to note that you can’t check if the point is minimum/maximum just by plugging in another value satisfying the condition and comparing it to the value at critical point. This is because minimum or maximum you find is LOCAL, so plugging other values is not enough. For example, think of the graph y=x^3-x^2. Its critical point is at 2/3, and it is local minimum. However, if you plug -1, you get even smaller value.
Exactly what I thought. So how do you check if it's max or min?
@@LuckyCrab_ there are sufficient conditions for both maximum and minimum values :)
For maximum, derivative at point must be zero AND second derivative must be negative.
For minimum, derivative at point must be zero AND second derivative must be positive.
By second derivative I mean taking first derivative (that returns a vector of functions), and differentiating each function once more. It will result in a matrix and then you should plug in point you want to check. After that, you need to check if the matrix is positively defined, or negatively defined.
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Professor Organic Chemistry Tutor, thank you for using the method of Lagrange Multipliers to find Maximum and Minimum values of a function with one and two constraints. Lagrange Multipliers has many applications in Economics. Lagrange Multipliers requires solving systems of nonlinear equations. This requires some tricky algebraic manipulation. This is an error free video/lecture on CZcams TV with the Organic Chemistry Tutor.
That's a great explanation. Thank you for posting. Do you have a video on how to apply L.M. to a non-linear regression problem with constrains,when I have initial guesses for my variables X, Y, Z. I can calculate the derivatives and the constraints numerically. and, of course, there is no way on Earth, the partial derivatives with respect to each adjustable parameter will give me the same Lamda in all equations. how would one iterate and adjust the initial guesses of the adjustable parameters to satisfy the equations?
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how do you know which points fit in the constraints other than the one that you calculated (2,4,8)?
^
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at the first example, how would you know that it is a min or max and how to find the other points?
I have the same question
You choose any 2 values for x and y and then solve for z. There’s your point.
@@kapjoteh he can also flip the value:)
way late, but you can also check the derivatives/second derivatives at that location and around it, I think
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Great video.
Question: The values you are using to show if its a local min or max, where do you get these numbers from, are they just pulled from thin air???
When determining if points are at a minimum or maximum, a set of figures can be chosen based on trend analysis. I want to know how it's done
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Hi sir.
In the first example, how do we know whether it is a minimum or maximum?
@Immanuel He compared it to another point that also fit the restrictions.
@@ergar90 …but is it not possible for such value to represent a saddle point? According to the second derivative test, it in fact should hold that at point (2,4,8), f attains a saddle points (Hessian matrix has determinant less than zero).
@@jacobguerreso675 the determinate is 8 tho?
fxx is 6 & fyy is 2 fxy is 0
6×2=8
@@roxas4587 the Hessian matrix would be the gradient times it’s transpose… at least, I believe so? Meaning that in this instance, the Hessian would just be a diagonal matrix of inputs 6, 2, -4 => determinant = -48
@@roxas4587 and of course, it’s also possible to check whether we have a max/min via definition using R3 balls/R2 circles/R1 intervals (by definition, if for all positive real radii “r” there exists a point greater AND a point less than f(a) in the ball/interval thing of radius “r” around point a, then we have a saddle point at point a given “a” is a critical point).
thank you so much
Sir, Do you have the video explanation about Fermats theorem, Abelian group, Homomorphism, kernel and image of homomorphism, isomorphism, Euler's generalization, Lagrange’s theorem,
How do we know that point (2,4,8) is min ? at 05:56
Plug in another point and see if it's higher or lower than (2,4,8)
how are you finding other points that fit the constraint
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Hi sir, can you help me solve this question Find the point (x, y) with the largest y value lying on the curve whose equation is y2 = x − 2x2 y.
This guy is better than my professor that I pay 10k+ a semester for
How do you know which points to pick when you're verifying the maximum and minimum values into the constraint equation?
It really doesnt matter. if the point you pick has a value larger than the point you find then that means that it cant be a maximum.
Ist there anyway to test if lambda is minimum or max without guessing or inputing a random number that equal to the constant, it feels like it's going to take time if you're on an exam and trying random numbers idk these might be a dumb question tho
i understand so much better now
son örnek çok güzeldi. last example was really good.
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I have one big question though: WHY does this work? Seems like magic.
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At the extreme values, the constraining function g(x,y,z)=k and f(x,y,z) share a tangent plane to their level surfaces. What we're really doing, therefore, is saying that they share the same unit normal (gradient) vectors at that point. So grad(f)=lambda*grad(g)
Thanks!
How to find those points that satisfies the constraints, when confirming the point p we got is the minimum
Hey , i don't know if you'll see this , but what is i'm given something like f(x,y)=xy^3 with a constraint of x^2+y^2=a^2
how do i solve this if a^2 isn't a number like "4" or "6" or any other normal number
Can you make some Barycentric geometry videos ?
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I’m literally sitting in calc 3 watching this on mute bc it’s more helpful than my professor in half the time
thank you
What about lambda equals zero for 3
Is it just a random point or is there reasoning for the second and third point examples he puts
My professor keeps taking points off my test because I'm using different methods. I don't really care tho, I'm actually learning with you😂😂
Your teacher is a bitch. Wtf lol. You should be able to use whatever method you want. This is stupid. You should complain to his higher ups or something
lol happened with my algebra 1 teacher. he gave me an F on a test for using derivatives to calculate the max/mins of parabolas instead of the -b/2a sh*t even though I got everything right. dropped his class and got a perfect score on the EOC. needless to say some teachers are annoying for zero reason
if your method works, use it, but hopefully u got a good grade nonetheless 😥
@@Gqtor well duh you're taking algebra 1 and using calculus on your test. I would have taken points off as well. He is testing your algebra skills not calculus.
@@KR-kk9fh i mean im in college now, but i disagree with that opinion. if you have a method to solve a problem, you should be able to use it. the real world isn't "hey find the peak of this parabola using ONLY algebra" it's just "find the peak of this parabola i don't care how you get it just put it on my desk in 10 minutes".
@@Gqtor the problem is, you should know why the method you use works. Have you proved the formula of a derivative of a parabola and the necessity and the sufficiency of an extremum?
Can someone tell me where he got 4,-3,7 from at 7:15
can you also explain why and the real life appliance of these formula not only , there is this , there is that, we need to do this, we need to do that, can we have why part also, thx!!
I have an exam today and this is very hel
i like this method way more compared to my professors way of doing the problem