Inverse Square Law ( Math Word Problem)
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- čas přidán 2. 10. 2017
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This video is from our inverse square law series.
In this video, you will see many step-by-step examples in how to perform inverse square law word problems.
The inverse square law in a fundamental concept within radiography. Through the use of the inverse square law radiographers are able to calculate x-ray photons intensity and radiation dose.
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I now finally understand the inverse square law! Very nicely explained, thank you.
Wonderfully explained. This video will help many students to better understand this concept.
Great video! Simple. Clear. Easy to follow.
Best explanation yet! thank you, your rewording of the equation makes this much more simple to solve for in my mind.
I never leave comments on videos but here I have to say thank you! Finally an explanation I understand!!! I appreciated this video!
Great to hear! Have you checked out our website, www.radtechbootcamp.com
Great refresher and the "new" formula is just better!
Thank you so much for such a nice and simple explanation. Great job!
These videos are so helpful, thank you!!!!
Awesome thanks! Great help.
Thank you so much! I understand it so much more now!
In all examples: after the squares of the distances are calculated you MUST do the division (1600 over 3600 = 0.44) THEN you must multipy that figure by the 1.2 mGy to get the new dose = 0.44 X 0.44 = 0.53 mGy.
Thank you so much! This is the first video that's actually made inverse square law make sense in terms of radiology! You've saved me for my radiation physics test
Agree
That’s great to hear! Have you visited our website, www.radtechbootcamp.com
Excelentísima explicación!
The teacher cancelled the two lectures that were supposed to be covering this and now we have a test on it. (SHOCK)! Thanks for helping me so I can at least have a better chance of passing this test! :)
Glad it was helpful!
you are such a life saver. saved me for my geology test lol
Thankkkkkkk youuuuu for your time!!!!
Thank you so much!!!! This video made the formula so much easier.
You can see more through our online learning resource. www.radtechbootcamp.com
Thank you! I actually understand now
This is very helpful. Thank you, sir.
thank you so much this helped alot. i finally get it. i have an imaging exam monday for my radiology program. Thank you!
Glad to hear! You can view the more videos at www.radtechbootcamp.com
Love this video! Helped so much!
You can purchase the full course at www.cloverleaflearning.com
Great explanation , thanks
Im a radtech students im struggling a lot with this one u make it easy thank you .
You can view more videos at www.radtechbootcamp.com
Thank you this was so helpful
Thank you. 💖💖 omg I was gonna cry then you made everything make sense.
In the first example where distance 1 is 72in and distance 2 is 36in the equation still works but isn’t necessary bc the inverse square law also states that if your distance is cut in half the intensity is 4 times as much and if you double the distance the intensity is 1/4. This means you can just multiply the original intensity of 0.01 mGy by 4 to get 0.04 mGy bc the distance was cut in half from 72 to 36.
Thank u so much!
thank you so much for making this video. I'm going for my radiography NDT level 2 in about a month so I"m trying to freshen up.
Did u pass?
Yes I did pass. Sorry for not replying sooner.
very well explained thank u
YOU ARE THE BEST, . NOW I KNOW HOW TO SOLVE THIS THING NOW!!!!!!!!!!! THANKS MAN!!!
Hey there, just want to ask, what are some other technical/mathematical/physics related topics do radiographers study?
Rockstar explanation , I hate math but this made it easy peezy
I have a test tomorrow and definitely will help out
THANK YOU !!!!! You are way better than my professor 🙏🙏🙏
Glad we could help. You can get the hundred more videos at www.radtechbootcamp.com
that was very useful thanx
wouldnt it be the I2 going to the other side ?? not saying its wrong or anything because I haven't had algebra in a while but just a question
I like that you clarified that if the distance increase or decrease. Then your answer will be the opposite of distance result. BUT..... if a student did not know how to perform the calculation with the original formula, WHY would you show another formula.(that you prefer) To add confusion to an all ready confused student WHY....WHY.... add confusion on top of confused.????
I agree 👍
This may be a silly request but do u know of any videos that have a step by step on using a scientific calculator to solve radiation safety math questions.? Thank u
1.600÷3.600 = .44 I was having the same issue this worked
I don't get how you did your math at all. I get the squaring each number but what did you do to get your answer.
A big ? Brother. Same when im doing computation.
In bushong chapter 8 there’s a problem where 1.1 is squared but it is still 1.1 why is that?
Dose this work, when looking for distance 2, if u sq. Root the the final answer?
Correct, same form for the equation, but root the final answer.
How to compute to get 0.04 ?
Is there a video where the distance AND also the mAs changes?
Hi Hamza, did you mean that? czcams.com/video/QThaEhsq-p0/video.html
But the 3rd one answer was-0.19
1 Divided by 5 =0.2
And 0.2- 0.01 is equal to=0.19 but the answer was 0.04 How sir 🙏
Please help to understand
I thought you need to flip the numbers. And when I did I got 0.0025 as my answer I don’t I understand why he didn’t flip them
ok i was over thinking, if dis is decreasing then the exposure increases, I always thought it was opposite, im visualizing it and over thinking. nope overthinking again dugh,
The last problem was wrong I guess ?
Answer wrong ....but you 0.01*2=0.2