Banked Turn with Friction - Physics of Speed Limits on Banked Curves
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- čas přidán 13. 06. 2022
- We take a look at the general case of finding the maximum speed at which a car can drive around a banked curve without skidding out. 0:00 We set up the problem using F = ma (Newton's 2nd Law) in the vertical (a = 0) and horizontal (a = mv^2 / R) directions to 4:17 relate the maximum speed to the ramp angle, radius of curvature of the road, and the coefficient of friction. Finding the speed limit on a banked curve is a very standard problem in mechanics in undergraduate physics, AP Physics, and IB Physics, and is useful for those who design banked roads. 7:48 Finally, we show the specific results for maximum speed vs. ramp angle for the specific case of an exit ramp radius of curvature of 100 m, acceleration due to gravity of 10 m/s^2, and a coefficient of friction of 0.9, which is reasonable for a dry day for rubber on asphalt. In addition, we explore what would happen if the road were unbanked and if the road were banked (tilted) the wrong way.
you just saved my physics grade. 100% soooonnnnnnnn
why isnt the value of N equal to cos(theta)*mg? isnt it usually the case when objects are on a curb?
Thanks. I'm in a horribly run physics course at the moment, and this really helped me to understand the problem.
Brilliant video. What equation did you use to get that graph? I don't know if I'm being completely stupid but I gave a graphing calculator the equation shown with the numbers given (R = 100, etc.) and got a totally different tan graph, and now I'm confused. Also, I used this process to find the max speed with different dimensions (R = 15, theta = 75, and COF = 0.32). Putting this in my calculator gives me a math error, as the denominator ends up negative. What does that mean in the context of turning? Are those just unfeasible dimensions? Hope you can help clear this up.
I am confused, what is the difference between v²=R.g.tan theta and the above equation?
what about mg sin theta when adding the sum of forces in the x direction (the car is on an incline isn't it?).
just want to say you're a lifesaver - really appreciate how visual your diagrams are, finally got my head around it :)
thank you so much, i literally couldnt find anyone else doing this type of problem
thanks a lot. finally makes sense. i guess my way of doing FBD where gravity is off to the side and everything else on the axis's doesn't work for this kind of problem although makes other problems a lot more convenient.
Better explained🎉🎉🎉
Great video. I have always found banked curves on roads and highways to be aesthetically pleasing.
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