Statics 7-28| Determine the internal normal force, shear force, and moment at points C and D

Question: Determine the internal normal force, shear force, and moment at points C and D in the simply supported beam. Point D is located just to the left of the 10-kN concentrated load.
Problem 7-28 from:
Engineering Mechanics: Statics, 14th edition
Russell C. Hibbeler
Thank you guys for watching.
Please let me know if you have any comments or suggestions and also if you have any other problem you would like to go over with.

[@sothasinmax]

Thank you so much, having a very bad time with distributed load when cut at point c this really help.

[@gerxi84]

i love you bro you're saving my life rn

[@mukukakalumba9280]

Excellent 😊,clear explanation point nailed , thank you for making it simple.

[@ankushraj642]

It's very much helpfull buddy...
Thanks alot..

[@dilacigdem4446]

You look so young whereas you solve the questions very professionally. Great video:)

[@LearningbyTeaching]

Hey Dila, thanks for the comment I am happy to help! :)

[@SalmanKhan-xj7jz]

Really helpful video, you cleared all my doubts about this type of problems

[@LearningbyTeaching]

Thank you for the comment. Glad to hear the video was helpful!

[@luisamatos2080]

Very helpful. Thank you so much ;)

[@LearningbyTeaching]

I am glad the video was helpful to you!! ;)

[@jasonmarx9715]

i got this in ma assignment , danko

[@laronaolekantse7081]

sir how did you dertemine that the distance between Ay and 9KN force is 1/3 of the base ?

[@janniswuyts]

legend

[@top437_]

how can we find the equations of internal forces?

[@alia-ux7sr]

hello sir... can i know for the first equation.. how do you get the 1/2 for the FA=1/2(3)(6)=9kN..actually i have forgotten the equation'' i've studied . thanks for your helping

[@tristancoronado8210]

Hi, the resultant force for a distributed load that takes the shape of a triangle can be calculated by multiplying one half the peak value of the distributed load with the distance over which it acts. Essentially, you are applying the equation of the area of a right triangle.

[@veeraveera6516]

Which book your refering for this sir? Please suggest me. I'm from India

[@LearningbyTeaching]

Hello the book I am using is in the description which is:
Engineering Mechanics: Statics, 14th edition
Russell C. Hibbeler

[@veeraveera6516]

@@LearningbyTeaching Thank you sir

[@younglegend4535]

Thanks? This helped me alot!
Would u be able to help me with a task im struggeling with?

[@LearningbyTeaching]

Hello, I am currently only doing videos of Dynamics my friend (from Hibbeler book).

[@iamilein1792]

I don’t understand how you get the rectangular height?

[@LearningbyTeaching]

Hello Iam, the height was calculated by knowing that from point A it takes 3 meters (x-direction) to go down the original 6 kN/m in height. Point C its located at the middle x-distance (of the 3 meters mentioned before), and by this we can calculate that the height will also be in the middle from original height (3kN/m).
I hope this clarifies your question :)

[@joexue8667]

@@LearningbyTeachinghey there I wonder how the 6kN/m turned to 3kN/m when getting the height.

[@joexue8667]

@@LearningbyTeachingoh I get it now, nvm.

[@tehoais1790]

Can I know why 9(1) in moment A calculation?How did you get 1?

[@Brickswol]

When he resolved the distributed load, since it is a triangle, the new distance from the edge is one third the previous distance. So 1/3 of 3m is 1m.

[@talonsewnath6020]

For calculating the moment about A, why have you disregarded the weight of the beam

[@LearningbyTeaching]

In this type of problems if the weight of the beam is not given, you could assume that its negligible.

[@talonsewnath6020]

@@LearningbyTeaching thank you

[@waterboykyle]

i love u

[@sanjana-uw4no]

how can i contact you?

[@sanjana-uw4no]

??

[@sanjana-uw4no]

??