Determine the discontinuity of the function

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  • čas přidĂĄn 30. 08. 2017
  • 👉 Learn how to classify the discontinuity of a function. A function is said to be discontinuos if there is a gap in the graph of the function. Some discontinuities are removable while others are non-removable. There is also jump discontinuity.
    A discontinuity is removable when the denominator can be factored such that the factor that makes the function discontinuos can be cancelled out with its common factor in the numerator. Otherwise the discontinuity is not removable.
    A discontinuity is said to be a jump discontinuity when the function approaches a certain point both from the left and from the right but the function is not defined at that point.
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Komentáře • 33

  • @ReedBourgeous
    @ReedBourgeous Před rokem +192

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    • @gabrielruizz2314
      @gabrielruizz2314 Před rokem +3

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      @foodisgood7607 Před rokem +8

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    • @L0ck1n
      @L0ck1n Před 9 měsĂ­ci

      @@foodisgood7607 fr he explains it so well

    • @cresentbutterfly2794
      @cresentbutterfly2794 Před 5 měsĂ­ci

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  • @leopearce649
    @leopearce649 Před 11 měsĂ­ci +7

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  • @airborne2876
    @airborne2876 Před 6 měsĂ­ci

    Man is better at getting to the meat and potatoes of a subject than my college classes.

  • @user-mp1jc5vh9r
    @user-mp1jc5vh9r Před 3 lety +3

    Here comes the hero without the cape
    You saved the day

  • @jodyanneubalde9043
    @jodyanneubalde9043 Před rokem +1

    Hi sir, what would i do if i am ask to find the value of x for which the function is discontinous.. for example 3x/x-5, do i have to find its limit? Then graph?

  • @mlninja3283
    @mlninja3283 Před 2 lety +2

    what if the function is not a fraction how do you find the value of x?

  • @XOFlaming
    @XOFlaming Před 7 lety +10

    Informative -!-

  • @shayaana982
    @shayaana982 Před 3 lety +3

    Hey, If I have an equation in which two different factors are cancelled out when factored, how do I know which one to use for the x value of my POD? Are there two PODs?

  • @Carpe_Diem_641
    @Carpe_Diem_641 Před 3 lety +4

    Iam confused.Is this function discontinuous at x = -2?

    • @jmeib
      @jmeib Před rokem +3

      no it's +2. because if you use x = 2 the denominator would equal zero. and that's not allowed

  • @Aurora-pp3cs
    @Aurora-pp3cs Před 5 lety +8

    I am confused. Wouldn’t there be an asymptote at x=2? Instead of hole?

    • @dozen2245
      @dozen2245 Před 5 lety

      Yeah me to like if x≠2 it should be an asymptope

    • @fredmirimo8195
      @fredmirimo8195 Před 5 lety +11

      There will be no an asymptote at point x=2 because it is a removable discontinuity instead we will have an asymptote when we come to essential discontinuity

    • @kifter4254
      @kifter4254 Před 5 lety +6

      When the top and bottom cancel out like that, theres a hole. In this case, a hole at x =2

    • @elizabethgagarin6443
      @elizabethgagarin6443 Před 4 lety +1

      Razia Sultana Shushanta an asymptote is an indicator of discontinuity

    • @onatyarclar3938
      @onatyarclar3938 Před 3 lety +2

      after canceling out, if there was still a value that makes denominator zero, that would be our vertical asymptote :)

  • @sneedle252
    @sneedle252 Před 11 měsĂ­ci

    How is this not simply the continuous function f(x) = x+2?

  • @infinix2003
    @infinix2003 Před 4 lety +4

    you cannot cancel out (x-2) without applying limits

  • @monikamusa6644
    @monikamusa6644 Před 3 lety

    Teacher u write discontintous but u did continious

  • @BayouboiiKi
    @BayouboiiKi Před rokem

    I’m here cause of NDT

  • @nerm8275
    @nerm8275 Před 2 lety +3

    huh