Please sir, at 9:10 i don't understand why did we take v2 to be negative? and do we always consider at 8:37 that there will be positive up and negative down?
At 9:10 Ideally the current is supposed to flow from the positive terminal at V2. But since we take 2v as reference voltage and we take the clockwise direction, V2 will move opposite to 2v hence V2 will be negative. At 8:37 Yes, negative is to ground.
Yes, the difference is where you apply kcl and the node. If one quantity is entering the node and was positive, if the direction changes, it will be leaving the node and this time negative
We have to demand corrections on books and ideas. In real world, there is no such thing as current source without voltage source. A circuit showing only a current source is fake idea. Where can you find a current source? This idea is meant to confuse students.
He has a point. I have this in my own notes concerning current sources. I think it would be safe to say that inherent within the symbol of the current source there is a Voltage. Since Voltage is a requirement for all circuits, including current sources, current source is just a specialized application of a Voltage source. 😅, did I confuse you more 😂
When a voltage source is found between two node reference nodes, a supernode is formed. In this case, the element in parallel with the voltage source goes away.
Since there is a voltage source in between the two non-referenced nodes, a supernode is formed, hence a supernode is formed and the element in parallel with the said voltage source goes away.
We assume conventional flow of current which says that current leave the positive terminal of a voltage source, an thats a positive current. Reference source is the 2v. We take the clockwise direction, going round the loop, our reference current opposes that of v2 hence that becomes negative and that of v1 is in line with the direction we took, ie. Clockwise, hence v1 becomes positive.
God bless you very much
You really improved my capacity of understanding 👏👏👏
Thanks for watching too
I finally understood supernodes, thank you so much
You are most welcome. Please where do you watch from?
Turkey@@SkanCityAcademy_SirJohn
Please sir, at 9:10 i don't understand why did we take v2 to be negative? and do we always consider at 8:37 that there will be positive up and negative down?
At 9:10
Ideally the current is supposed to flow from the positive terminal at V2.
But since we take 2v as reference voltage and we take the clockwise direction, V2 will move opposite to 2v hence V2 will be negative.
At 8:37
Yes, negative is to ground.
Many thanks for your Videos. Do you have the Nodal Analysis involving Voltage Sources (Supernode) 2?
I think I should have, please check the playlist...
@SkanCityAcademy_SirJohn I did already but it's not available. You can share me the link in case I'm missing something. Thanks.
I think I don't have
Sir please help us with that explanation in another video. Nodal Analysis involving Voltage Sources (Super Node)2.
@mohamedsillah9885 noted
Lovely explanations. Thanks a million. Pls which textbook can you recommend for this?
You are most welcome. Alexander and Sadiku - fundamentals of electric circuit
Please sir For the first eg. Can there be a case where the 2A is directed downwards or the 7A is directed upwards. If yes ,how are you gonna solve it
Yes, the difference is where you apply kcl and the node. If one quantity is entering the node and was positive, if the direction changes, it will be leaving the node and this time negative
@@SkanCityAcademy_SirJohn .....Thank you very much.... May God bless you
Amen, may God bless you too
Please in Example 1 why did you ignore the 10ohm resistor that was parallel to the 2V source?
I think I explained the concept of super nodes there. Do you understand that concept?
@@SkanCityAcademy_SirJohn ohk. Thank you. I got the answer now. Love your teaching
Pius Oblie you are most welcome. Where do you watch from?
@@SkanCityAcademy_SirJohn Ghana. University of Ghana, Legon.
Pius Oblie oh okay, thats nice. Good luck
We have to demand corrections on books and ideas. In real world, there is no such thing as current source without voltage source. A circuit showing only a current source is fake idea. Where can you find a current source? This idea is meant to confuse students.
😂😂
He has a point. I have this in my own notes concerning current sources. I think it would be safe to say that inherent within the symbol of the current source there is a Voltage. Since Voltage is a requirement for all circuits, including current sources, current source is just a specialized application of a Voltage source. 😅, did I confuse you more 😂
Interesting ideas, I love it. Thanks so much for your contribution. I'm grateful.
in the fist problem where did the 10 ohms go?
When a voltage source is found between two node reference nodes, a supernode is formed. In this case, the element in parallel with the voltage source goes away.
Sir, for the second one are the answers not supposed to be v2= -6 and v1=-15?
No please
Then i’m a big confused cause I don’t see where I went wrong😭
kindly follow my solution carefully@@ntwisisochauke3495
Thank you
Most welcome
Reason for excluding 10ohm
Since there is a voltage source in between the two non-referenced nodes, a supernode is formed, hence a supernode is formed and the element in parallel with the said voltage source goes away.
What textbook you use ?
Alexander and Sadiku fundamentals of electric circuit
can you solve the v and i in 11:54
That's exactly what I solved in the video.
Thanks so much bro♥️♥️
Most welcome
I really did not understand the part were you summed the voltages. Like the sign conversion pls help sir.
can you please state the time in the video so i help you out?
9:11s
We assume conventional flow of current which says that current leave the positive terminal of a voltage source, an thats a positive current. Reference source is the 2v. We take the clockwise direction, going round the loop, our reference current opposes that of v2 hence that becomes negative and that of v1 is in line with the direction we took, ie. Clockwise, hence v1 becomes positive.
@SkanCityAcademy_SirJohn thank you so much sir. God bless you ❤️
You are most welcome. Where do you watch me from?
Nice class
Thank you so much