In which I solve an EXTREME SUDOKU for Twitter
Vložit
- čas přidán 27. 03. 2022
- I'm Scott Strosahl, and today I'm solving a sudoku that was requested by Kia7 on twitter.
You can try 'extreme' sudoku yourself at tinyurl.com/2p8nkddk
Become a member of the Stro-Solves CZcams channel - / @strosolves
Want to support me on Patreon? You can do that here - / strosahl
Puzzle submission form - scottstrosahl.com/submissions/
Scott's Video/Puzzle Spreadsheet - tinyurl.com/Stro-Solves
Come discuss this puzzle with us on discord - / discord - Hry
I haven’t played much sudoku, I know how it works and thought it was pretty straightforward until he started speaking a foreign language going at light speed
😂😂 same
I know right
That 1 and 5 pair would kill me if i tried this
there is probably a normal way to find a solution with a known technique. but probably using a full marked board and not just marking some cells
anyone else find it weird that Scott's thought is much quicker with a harder puzzle like Sudoku than it is with easier puzzles like Wordle/variants ?
Maybe cause all these wordle variants are still not even a year old while sudoku he could’ve been doing since childhood
His thought process is really fast for the worlds variants as well though????
@@henrymarks1632 no it's not. It's terribly slow. :)
@@kurzackd he's strategizing, and not just recklessly putting a word he just thought of.
@@yuripaelden419 nooo shit? :D
Clever puzzle and nice solving, very enjoyable to see the logic presented so clearly, and at about 10x faster than I would get it.
I used the slot machine technique on the 1s and 5s which essentially worked the same in figuring out box 5. Good puzzle and very interesting to see your approach, thanks
After watching the video, I average 11 minutes in extreme now. Thank you so much! Nice methods and app/website.
So glad I found your channel. :) I just started playing again - after not playing for many years. I decided I wanted to avoid doing dishes today.
16:29. I noticed 1 and 5 had the classic markers for a swordfish (3 digits in different boxes that share no columns or rows) while not a swordfish, realising there was definitely something funky going on there, with a little logical inference got me going pretty quick.
Bro opened my eyes to a new way of thinking
I was impressed with the first 4 never thought of looking it that way
Just over the video length (14:59) for me! My hope faded quickly, I didn't spot anything that I probably should've to get me to a quicker time, I sort of just did it in my head like I do with classics, and I got stumped for about 45 seconds trying to disambiguate a string that I mistakenly added a number to that shouldn't have been there! Whoops. This was a cool puzzle and thank you, Scott, for the reminder that I need to work on my classic sudoku technique! :)
Love your videos! Always helps me with different strategies I can use for wordles :D Love from India..
Me too i am from India too
Cap
Fax
Sussy
Caught in 4k
18:52 for me, I struggled with the phistomephel ring for 10 mins straight to find where the 1s go lol.
Solved in 14:01. I marked all the cells that could be a 5, by trying all three possibilities in block 3, we can know in all three scenario, R3C5 is not a 5 => pointing pair in block 2, R6C4 also not a 5. For 1, also marked in color, then we can see that if R2C5 is 1, then no place to put a 1 in block 5.=>R1C4=1 R6C4=7 R3C4=5, then the puzzle will fall apart.
Many thanks for introducing this puzzle to us😊
What app are you using for these puzzles, these pencil marks and colors look great
Great intro! I loved it!
Loved that intro Scot!
I couldn't understand how you filled 1 and 5
Start with crane ,shout and dream
Took me 10 minutes longer but I did it notation free. I found that once the 68 and 9 were identified in box 8, either position for 1 in row 7 put 1 in r1c4. I won't say it was easy after that but it certainly pushed things along a bit.
Sus
Cap
Cqught in 4k
Unique rectangle on 15 in block 4 and 5 would eliminate the 15 in r6c3...
I love ur videos, and for wordle, you should start with audio, fruit, and nymph
Nice puzzle and solve. I solved it in 13:43.
For the break-in I found a finned swordfish on 1s in columns 2, 4, and 8, with the fin being the cell r2c8. This eliminates 1 from r1c9 (either the swordfish or the fin), limiting 1s to row 2 in box 3, which places 1 in r1c5, which you also found.
what
@@JDBJake sodoku is crazy man
@@JDBJake my thoughts exactly
Ein interessanter Sword-fish mit einem fehlenden Kandidaten, dafür aber der Finne. Die 1 geht aber nach A4.
This puzzle took me 27 minutes and 1 hint
But 0 mistakes
5+6+6=17 given clues, putting the puzzle at an advanced level, yet not so ’extreme’ as claimed. Of the clues, 489 are singles, 2367 are doubles, three sets of [15] coupled pairs,on cols 1&6 and on row7.
Before we kick off the preliminary sweep across the whole board, with eyes wide open, we should spot a few immediate takeaways :
7 on c1@(11), (=>6 on c1 B7), 3 in B8@(84) to be followed immediately by 7@(95)=> [68] tcp on r7B8 between cols 5&6, leaving 9@(74)(which can actually be pinpointed by direct point counting and that’s a hidden 9 for u) => in hot pursuit, 4@(44) (two ways of going abt it : by eliminating 3&9 from cell(44) = [349] by hard count OR by visual spotting : [715] given on r4 being off c4 are to occupy the remaining three open cells outside of (44) on c4, leaving 4 @(44). (A lot of novice may miss this but no harm done it will show up eventually)
Now here comes the takeaway for the trained eyes, the three pairs of [15] given on c1,c6 and r4 , all cutting off r5 ===> [15] cp(conjugate pairs) on r5 @ P(53)&Q(55)!,leaving 2 splt on r5 @(51))&(56).
Now scanning for splits across the board:
Being the majority clues we start with 1&5 :
1 split in B2@(14)&(24), this will prove critical, split on r1,r7,c2&c8.
5 split on r1&r7. (That’s all)
Now note! 1&5 share same cells on r1 at R(14) and on r7 @ S(73).
A million dollar question : are the cells exclusive of the other candidates? Answer is a resounding yes!
Here’s why: 1&5 not at R => 1@(19)&5@(17) ==> both on r7 at S, a No-no! So R=[15].
By same reasoning, we have S=[15] => 2 split on r7 @(71)&(79).
Now we have [15] cp on c3 @ P&S=> [15] cp in B4 @ P&T(62) (hopefully it’s obvious to u).
Now the split of 1 in B2 comes to play!
Claim: whether 1 is in B2, it always lead to 1@P!
Obvious if 1@(25).
Next 1 @R => 5 on r1@(17) => 5 on r7@S => 1@P!
There are other ways to prove 1@P : whether 5 is on r1 , it always lead to 1 @P; likewise for 5 on r7; OR proof by contradiction: 5@P would lead to 5@(17)&(77), a No-no! two 5s on same c7 , or => 1&(24) ==> Q= Zero!
However there’s a better and prettier approach (and without the help of 5) :
1 forms a closed loop by
starting from (24) B2=> 1@ P => 1 on r7 @(79) and ending on r1 @ R, a No-no.
Therefore 1 in B2 is at R => 5@(17) and 1 on c9@(79) => 5@ S and 1@P and so forth.
There is a technical term in Sudoku bag of tricks to describe what we have been going through: XY wing.
Now we can with confidence declare the rest is history!
Try to do it on your own effort , but if u get stuck at any step,then take a peek at what follows up.
First we proceed to complete all the 1s and 5s and helping to pick up other candidates along the way:
So 1@P => 1 on c2@(92), 5@QT&S => 1@(79)=>1 on r1@R => 5 on c4@(34), by virtue of 5 given inB8,on r4,and uncovered @T , all three off c4,to be followed by 7 on c4@(64), whereby leaving 4 on c4 @(44) (as promised it will show up if u fail to spot it earlier),and also => 5 on r1 @(17) => together with 2 given on c7,and 2&5 given on r9 , both outside of B9, [25] tcp on r8B9 bet cols 8&9 => 2@(89) which with 1 uncovered @(79), and in tandem with [12] given on c7, both outside of B3 => [12] tcp on c8B3.
Now 1 uncovered @(79) => 2 on r7@(71), by virtue of 2 given @(67) off r7 => in hot pursuit 2 in B7 @(42) by cc with the 2 given on r6 outside of B7 and 2 on r5@56) => 2 on r1@(13) (CIY) => with 6 given on c2 off r1 => 6 on r1@(19), leaving 2&8 cp on r 1@(12)&(16).
Also 2 uncovered @(71) leaves 4 on r7@(77). Note [25] uncovered tcp on r8B9 leads to 7 on r8@(87) which together with 4 uncovered @(77) => [47] tcp on c9B3, leaving [38]tcp on c7B3 bet rows 2&3.
Note 6 uncovered on r1@(19) B3 is off c7 and in tandem with 6 given on r5 also off c7 => 6 on c7@(97), leaving 9 on c7@(57) => 7 on r5@(58), leaving [46] tcp on c8B6 bet rows 4&6 => with 4 uncovered @(44), [16] tcp in B5 on r6 bet cols 5&6, leaving [39] tcp r4B5 ==> together with the [39] uncovered on r5, [39] tcp on r6B7 bet cols 1&3, leaving [48] tcp on c1B4 bet rows 4&5.
Now we return to Bottom Block : 2@(71) => [34] tcp on r9B7 bet cols 1&3 => 6 on c1&(81) leaving [89] tcp on r8B7 bet rows 2&3.
There's actually only one option for the one in box two. The other one is clearly unavailable. After this, the puzzle practically solves itself.
I mean, that's where I got to eventually, but it's definitely not clear that there is only one option at the start.
Thanks sir
Video 5 of asking for him to start with Other, Nails, and if you get lots of grays Pudgy ( you get all the vowels and t,h,r,n,l,s,p,g and d
Wordle suggestion: use the example words to start.(Weary, pills, and vague.)
I tried doing extreme level multiple times but couldn't solve it completely
What application are you using? I would like to use it as well. I'm unable to shade on the site I play on.
It's the CTC webapp
I just learned how to play a day ago
I confused again
Precisely Which sudoku app is this?
I have completed the extreme level in only 6 minutes and 37 seconds my highest record ever, without any help.
I have the data but I forgot to record it😢
Where do you play sudoku and GAPP puzzles
Hello big brother, first Take love from India ❤.
I also solve same way that you solved this puzzle except those note taking method. I don't know what is the exact method of focus on cell, row & column. If you help me it'll be very thankful for me. Take love in advance ❤. Keep it up.
This is extreme? I solved it in 13:33. My first move was a winged swordfish on 1s, so I missed the obvious 3 and 7s until much later. It's annoying to me as well. Why is this marked as extreme when I usually take around half an hour on some of the puzzles on the CTC site?
😴
He lost me on 689. How did he know a 9 would go in row 7, col 4?
This puzzle has 5+6+6=17 clues, putting itself on an advanced level,(but not quite as extreme as claimed,to me ‘extreme’ means use of brutal,monster,steamroller kind of force, but this is not so here,as u will see)with three given singletons 489(indeed two immediately obvious hiddens : 9@(74)by point counting 😮 &3 in Box 8@(84) by cc(crisscrossing)of the two 3 given on c5&r7 outside of B8,followed by 7@(95)B8,by virtue of 7 given on r7 outside of B8 (indeed one should able to see right away without hesitation that by virtue of 7&3 given on r7 outside of B8, [37] cp in B8 @(84)&(95))=> [68] tcp on r7B8 between cols 5&6,by virtue of [68] given on c4 outside of B8,thereby leaving 9 in B8@(74) and together with 3@(84)=>(44)=[4]by point counting or by another way of looking at it, 715 given on r4 off c4 have to occupy the other three open cells left on c4 =>4@(44). Btw, we have 3 on r9B7, 7 on r8B9 and 4on c6B2.
And two of given 2367.
Three given1& 5.
There is another immediate visual takeaway, viz[15] cp on r5 @ P(53)&Q(55), by virtue of [15] given in B6 and on cols 1&6, all three off r5!! => 2 split on r7.
Now time for the preliminary sweep across the grid looking for splits in boxes , on rows and columns and hopefully more hiddens:
Right away,with 7 given in Boxes 4&5, both off c1, 7 @(11).
Indeed it’s the distribution of 1&5 that demands our attention :
1 & 5 have splits on r1,(I assume u have a way to pencil mark splits on rows and columns,without using the Arabic numerals which are reserved for splits in Boxes. For this purpose l am using the Chinese numerals: 一二三四五 六七八九),on c2,r7,c8.
1 is split in B2.
Observe that 5&7 occupy the same two cells(14)&(73),but we can’t say at this stage for sure they are exclusive from other digits (however eventually it will be proven the case)
To a trained eye the intertwining of 1&5 deserves our attention.
There are several ways of attack: one is to show (inspired by the fact that 5 forms a fractured wing along r1&r7 with pivot on c7),whether 5 is on r7,it always leads to 5 on r5@Q with the help of 1 (CIY=check it yourself).
OR by contradiction, 5@P would lead to 5 on r7@(77)=>5 on r1@(14)=>1 in B2@(25)by cc of the two 1s outside of B2,one on r3&the other on c6 => Q=ZERO!! Therefore 5 on r5 has to be at Q! and 1@P.
At this stage 1 uncovered at P proves to be the breakthrough,the closure we are looking for.
Try for yourself. It will be fun. No more inductive but purely deductive logic will take u thru.
Here’s for the ‘novice’:
So 1@P=>1 on r7@(79)&on c2@(92)=> 1 on c8@(28)=> on r1@(14)&c5@(65),completing all 1s in the grid.
Now 1@(14)=> 5 on r1@(17)(here’s where 5 kicks in)=>5 on r3@(35) ,5 on r7@(73) and 5 on c8@(88)=>5 on c2@(62),completing all 5s in the grid.
Now 5@(34)=>7 on c4@(64) ,thus leaving 4 on c4@(44)(we however have known that).
Looking at B9, with 1&5 uncovered where they are , 2 in B9@(89) by the cc of the 2s given on r9&c7 outside B9(see how their strategic positions come into play)=>2 on c8@(38) .Now looking at row7, with 1&5 uncovered on r7,we have 2 given at (67) off r7=> 2 on r7@(71),leaving 4 on r7@(77) and 2 on r5@(56),plus 2 in B4@(42)by cc with 2 given at (67)=> 2 on c5@(25) and on r1@(13)[CIY],completing all 2s in the grid.
Note in passing,7 on r8 is at (87)=>with the 4@(77), [47] tcp on c9B3, leaving [38] tcp on c7B3, and 6 on c7@(97),by virtue of 6 given on r5 off c7,thereby leaving 9 on c7@(57) and [98] tcp on r9B9 => with 9 given @(18),[38] tcp on c9B6=> 7 on r5@(58),leaving [64] tcp on c8B6 bet rows 4&6, as anticipated by [46] already uncovered on r5, and on c7&c9,all outside of B6 => with 4@(44), 6 in B5@(66), leaving [39] tcp on r4B5 bet cols5&6 => [39] tcp on r6B4 (hope u can see it how), leaving [48] tcp on c1B4.
Also in hot pursuit, 3 given @(15)=> 9@(45) and with 7 uncovered @(95) =>[79] tcp on c6B2, leaving [28] tcp on c5B2.
Now with 6&9 uncovered in B9 on r9, off c1=> 6 on c1@(81) followed by 9 on c1@(61),leaving 3 on c1@(91) , resulting in [89] tcp on r8B7 bet cols 2&3, and [14] tcp on r9B7 bet the same two cols => [34] tcp on c2B1 and [69] tcp on c3B1 bet rows 2&3 [CIY, a good practice for novice].
Whoa! We are practically done.
Can u visualize how those tcps in the bottom and middle horizontal Blocks are broken down?
Those six chains of tcp between rows 2&3 are to be broken up by the two ’danglars’ 6@(24)&2@(38).
The end result of the puzzle looks pretty graphic,ain’t it? That’s why sudoku is described as a visual art
I don’t know if you’ve every tried killer sudoku? My 7yo brother and I really enjoy it
Yes, I've both solved and created quite a few killer sudokus in the past. They are a lot of fun!
What software is he using?
Start with my starting words, TEARS, POUND, CLIMB
I use to play actively and easily get uner 11min but now I'm bad at it and it takes me like 16
The 29th of March,s worldle is pretty easy ss well it is a well known country
You should try squardle
He already did. And not once.
I used the Empty Rectangle strategy to eliminate 1 from B5 and thereafter the puzzle collapsed
I love sudoku. But I need to learn how to solve extreme level. I came here but you don’t try to teach, right?
Hope you do a video teaching how to solve it. Thanks. 😊
Hello! Use “ELITE EIGHT SAINT PETER” at the start of your next wordle to celebrate St. Peter’s being the only fifteenth seed in ncaa history to make it to the elite eight!
Day 6 of me asking you to do TUBES FLING CHAMP WORDY for wordle
What soduko solver app or website is that?
there is link in the description
@@twieg Oh thanks
I’m sorry what
999 IQ dude here
Can someone explain to me why that's a 1 there at 7:29
I guess that depends which 1 you're talking about. Row 1 Col 4 was because of the 5 and 7 below, and the other two 1s (Row 5 Col 3 and Row 6 Col 5) were because of the previous work I had done finding the 15 cells that had to be the same (hence the coloring).
@@StroSolves now that that I realized it, sorry for not specific enough. Also thank you for the answer!
You should try a quordle with this strategy: WAQFS, VOZHD, BRICK, GLENT, JUMPY. You have to guess everything in 1 go but you have 25/26 letters covered, excluding the X.
It makes the game not fun bruh
You should start with the 4 words "flame brick podgy and shunt" it removes 22 characters
And the 6 to the 9 and oh that gives us 4 but wait oh I see 5 here 3 goes there and errh let look at this area 235 remove the 5 because we got one ryt here 😂😂😂
try an extreme killer sudoku
I've done many killer sudokus in the past (and even created many killer sudokus, some of which might be considered extreme)
But have you tried a completely empty one?
you should play escape room games
My wife and I love doing escape rooms!
@@StroSolves there are some nice games out there, namely escape simulator, i would like to watch you try those
hi
NO WAY YOU USED BOMBER BY RIOT AS YOUR INTRO SONG
I LITERALLY KNOW SOMEONE WITH THAT EXACT SONG AS THEIR INTRO
Great video but at least credit Cracking the Cryptic and their programmer as you use their app while solving???
I've mentioned what site I use before, but I guess I could point it out again. I think I'm just used to everyone knowing that website since I share a discord server with Sven (and a few other people)
Also Great video
First!
Can you give me a shoutout? Love your videos!
Could not get your logic…how a 7 you got in the fifth square… no satisfying reasoning ..sorry
This videos are not helpful. I got a sodoku that was super hard it was missing number 7 and 6. This people don't know
Wordle 282 6/6
⬜⬜⬜⬜🟨
⬜🟨⬜⬜⬜
⬜⬜🟨🟨⬜
⬜🟨⬜⬜⬜
🟨🟨⬜⬜⬜
🟩🟩🟩🟩🟩
Respectfully wtf😭respect to you from Morocco🤎🤎🤎