Python Binding a Name to an Object

Describes how Python does not have an assignment statement in the 'traditional sense' of its meaning. Instead it has names that are bound to an object. This video uses two programs and a model animation to help explain the Python mechanism for assigning when dealing with immutable integers.

[@boa2145]

Very interesting video about "binding a name to an object". Excellent!

[@johnphilipjones]

Many thanks.
Best wishes Phil

[@kenmeyer100]

beautifully explained!

[@srinidhiskanda754]

thank you sir, i just want to clarify one thing x = 2 is an object of class integer generally we follow traditional approach to create instance of class like this x = IntegerClass() then we assign x = 2. so here actually we directly assign value x = 2. so both are same right.

[@johnphilipjones]

x = 2 does indeed create an integer object. it is usual to describe this as implied creation.

[@vengtCent]

great explanation!

[@adiy77]

Excellent!! thank you

[@sumitborhade1883]

ayy thanx a lot for simplifying it so much!

[@XieQiu]

helpful!

[@robertbrooks4529]

Thank you!
bob

[@johnphilipjones]

Thanks for commenting Best wishes
Phil

[@dilshodrahmatov3058]

From this video I understood that in Python use to say "Binding" instead of "Box". Am I right?

[@johnphilipjones]

In Python a variable is a name bound to an instance of an object and the instance has the type.
Best wishes
Phil

[@kravec.miroslav]

So,... in other words: Everything is box, but the box doesn't contain value, but the pointer to an object?

[@johnphilipjones]

***** Yes but in Python it is usual to talk about binding names to objects

[@kravec.miroslav]

John Philip Jones what about properties? ... consider this:
x = getSomeObject()
y = x
y.a = 5
you don't only bind name 'y.a' to object '5', because name 'x.a' has the same value... How should I understand that?
Thanks :)

[@johnphilipjones]

***** The first line is not Python but lets assume that you mean x is bound to an object after the first line. Then after y = x BOTH x and y are bound to the same object. y.a sets an attribute of this object so x.a and y.a refer to the same 'thing'