Learn Implicit Differentiation Under 3.9667 Minutes!

Implicit differentiation is used to find the derivatives when we cannot write a function ‘y’ in terms of ‘x’ directly. Normally, we’re dealing with functions that can be separated in terms of x easily. In implicit differentiation, we differentiate it with respect to x, on every single term in the equation. After all, we rearrange the equation to solve for (dy/dx).
Chain Rule Explanation Video: • Learn Chain Rule Diffe...
Product Rule Explanation Video: • Product Rule Different...
0:00 When to use Implicit Differentiation
0:40 Why multiply by (dy/dx)
1:21 Example 1
2:52 Example 2

[@64_bit_coding]

This video is great it was explained so well tysm

[@YeahMathIsBoring]

Thanks!

[@jupa7166]

Very nice, I've learned something new! Thank You!

[@YeahMathIsBoring]

My pleasure!

[@TheSyporg]

Wow

[@aziqasri5435]

Thanks for making me understand more about this topic. I would like to ask does chain rule applied to all implicit equations? And if not, in what situation we can use it?

[@YeahMathIsBoring]

Yes it does! To clarify, chain rule is applied the on terms that have composition of functions, in which we differentiate the outer function without changing the inner function, and we then multiply it by the derivative of the inner function.

[@aziqasri5435]

@YeahMathIsBoring would like to clarify more about on terms?

[@YeahMathIsBoring]

@@aziqasri5435
For example: (2x-1)^2, this term can be said that it has a composition of functions. But how?
We let f(x) = x^2, and g(x) = 2x -1.
When we plug in g(x) into f(x), which is denoted by f(g(x)), it would be (2x-1)^2. Notice that it is exactly the same as the original term. Therefore, we can say that f(g(x)) is a composite function, and that's why (2x-1)^2 can be said that it is a term that has a composition of functions.
You may check out the video I uploaded to learn more about this in the chain rule topic: czcams.com/video/js8jOoWyZ2M/video.html

[@aziqasri5435]

@YeahMathIsBoring thanks again, good sir. Anyway, I have subscribed to you.

[@YeahMathIsBoring]

@@aziqasri5435 Glad to hear that! I appreciate it!