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Good job sister!

😮

Very nice nwannem

Can we do this? 4^n+2^n=6; (4+2)^n=6; 6^n=6^1: then n=1 ??

Good job!

I want the way u answer very quick and easy

y^(y√y) = (y√y)^(y) → let: a = y√y y^(a) = a^(y) Ln[y^(a)] = Ln[a^(y)] a.Ln(y) = y.Ln(a) a/y = Ln(a) / Ln(y) → recall: a = y√y (y√y)/y = Ln(y√y) / Ln(y) √y = [Ln(y) + Ln(√y)] / Ln(y) √y = [Ln(y) + Ln{y}^(1/2)] / Ln(y) √y = [Ln(y) + (1/2).Ln(y)] / Ln(y) √y = (3/2).Ln(y) / Ln(y) √y = 3/2 → y = 9/4

You do this so effortlessly

x^(x^2)=2^4 =2^(2^2) ==> x=2.

Great job ma ... Keep it up

I did ... a⁴ = (a - 1)⁴ a⁴ - (a - 1)⁴ = 0 (a²)² - ((a - 1)²)² = 0 (a² - (a - 1)²)·(a² + (a - 1)²) = 0 (a² - (a² - 2a + 1))·(a² + (a² - 2a + 1)) = 0 (a² - a² + 2a - 1)·(a² + a² - 2a + 1) = 0 (2a - 1)·(2a² - 2a + 1) = 0 /// case (2a - 1) = 0 2a - 1 = 0 a = 1/2 /// case (2a² - 2a + 1) = 0 2a² - 2a + 1 = 0 Δ = (-2)² - 4·2·1 = 4 - 8 = -4 √Δ = ±i√4 = 2i • root #1: a = (-(-2) + 2i)/(2·2) = 2/4 + 2i/4 = 1/2 + i/2 • root #2: a = (-(-2) - 2i)/(2·2) = 2/4 + 2i/4 = 1/2 - i/2 /// final results: ■ a = 1/2 ■ a = 1/2 + i/2 ■ a = 1/2 - i/2 => I T ' S A S Y O U R S O L U T I O N B E C A U S E I T ' S A V E R Y N I C E W A Y T O S O L V E T H E E Q U A T I O N . 🙂🙂🙂

And at the end of the day who really cares. And if it takes her that length of time to solve a fairly straightforward equation have all the students gone to sleep😂

9^10(1+1+1)=(9^10)×3=27^10

Answer is there by just looking at it

Ja, schon klar. Wurzel aus einer negativen Zahl.... Bei diesem i-Blödsinn steigt doch jeder normal denkende Mensch aus. Schon die Aufgabe selbst a = a - 1 zeigt doch, daß es hier keine vernünftige Lösung geben kann.

Sufficient grace Chinwedu

Great job ❤❤

X⁴=81,X⁴-81=0,(X²)²-9²=0,(X²-9)(X²+9)=0,(X+3)(X-3)=0,X+3=0,X=-3,X-3=0X=3,X²+9=0, (X+3)(X+3)=0,S={-3,3}.

D. It has to be dissolve completely

Obviously if you expand the right side you wind up with an a^4 that will cancel the one on the left. So this will just be a cubic polynomial, and that's readily solvable. On top of that, it's immediately clear that a = 0.5 is a real solution, so we could divide that out of the cubic and have a quadratic left. But, there is a better way to proceed. Do this: a^4 = (a-1)^4 1 = (a-1)^4 / a^4 1 = ((a-1)/a)^4 1 = (1-1/a)^4 So now we see that 1-1/a is the fourth roots of unity. So: 1 - 1/a = 1 1 - 1/a = i 1 - 1/a = -1 1 - 1/a = -i The first one of these leads to infinity for a - that's the one that goes away to leave us with just three solutions, as we decided right off the bat we needed (because the a^4 cancels from both sides). Now we can just solve the other three: a = 1/(1-i) a = 1/2 a = 1/(1+i) You can put those into a more normalized form if you want, with the i's in the numerators, but those are the solutions.

3 exposant 4

too straightforward

Did she really have to do that expansion into (a-1)(a-1) to do a simple square? Everyone with half an education and half a brain can either perform that directly or just remember the simple form of the result. She looks like a math teacher with a marginal education, like the dozens and dozens of high school math teachers I ran into in my 33 years teaching Physics!

a⁴ = (a − 1)⁴ a⁴ = a⁴ − 4a³ + 6a² − 4a + 1 0 = −4a³ + 6a² − 4a + 1 a³ − 3a²/2 + a − 1/4 = 0 (a − 1/2) ⋅ (a² − a + 1/2) = 0 a₁ = 1/2 a₂,₃ = 1/2 ± √(1/4 − 1/2) = 1/2 ± √(−1/4) = 1/2 ± i/2 a₂ (1 − i) / 2 ∨ a₃ = (1 + i) / 2 𝕃 = {1/2, (1−i)/2, (1+i)/2}

3+2 n'est pas égal à 6 !!!

Beautiful but you can also introduce Log base 10 to both sides at the initial point of introducing Log ❤

Vaya tontería! Si es todo directo e instantáneo.😂

I'm waiting for the checking

Thanks mam 🙏

Good job!

Good job!

720?

x=ln((1+sqrt5)2)/ln(5/3) , .

Great 👍

Nice explanation. I had the right answer, but cheated by calculating the value in my head and didn't have the algebraic expression. In my defense, its still early in the morning and I've just started drinking coffee.

Cool

You are right

3^20

Great job ❤

Right answer is C. 27^10

3^21

Good job.

Thanks for sharing

Great content

Good job

Good job

Keep it up

Why not teach topic one after the other. You just pick one question and start solving, I have watched your videos, you don't teach topics. How can we understand.

Wow 😮

9ice