- 65
- 242 852
Tät Ghosh
India
Registrace 21. 04. 2014
Mathematician from Calcutta, India. Special interests: Geometry, Topology, and Physics, Differential Geometry and Mathematical Gauge Theory.
Dominic Joyce - Riemannian holonomy groups, Lesson 15
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University.
qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
zhlédnutí: 232
Video
Dominic Joyce - Riemannian holonomy groups, Lesson 14
zhlédnutí 195Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 13
zhlédnutí 198Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 12
zhlédnutí 171Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 11
zhlédnutí 176Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 10
zhlédnutí 166Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 09
zhlédnutí 180Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 08
zhlédnutí 205Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 07
zhlédnutí 202Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 06
zhlédnutí 214Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 05
zhlédnutí 335Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 04
zhlédnutí 331Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 03
zhlédnutí 424Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 02
zhlédnutí 593Před 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Dominic Joyce - Riemannian holonomy groups, Lesson 01
zhlédnutí 2KPřed 3 lety
Masterclass by Dominic Joyce (Oxford University) at Centre for Quantum Geometry of Moduli Spaces, Aarhus University. qgm.au.dk/video/mc/riemannian-holonomy-groups-gauge-theory-and-instanton-moduli-spaces/index.html
Andriy Haydys - Higher dimensional gauge theory and Fueter maps
zhlédnutí 383Před 5 lety
Andriy Haydys - Higher dimensional gauge theory and Fueter maps
Andriy Haydys - Special Kaehler structures with isolated singularities in real dimension two
zhlédnutí 74Před 5 lety
Andriy Haydys - Special Kaehler structures with isolated singularities in real dimension two
Andriy Haydys - Seiberg-Witten monopoles and flat PSL(2,R) connections
zhlédnutí 116Před 5 lety
Andriy Haydys - Seiberg-Witten monopoles and flat PSL(2,R) connections
Andriy Haydys - G₂ instantons and the Seiberg Witten monopoles
zhlédnutí 135Před 5 lety
Andriy Haydys - G₂ instantons and the Seiberg Witten monopoles
Andriy Haydys - On degenerations of the Seiberg-Witten monopoles and G₂ instantons
zhlédnutí 117Před 5 lety
Andriy Haydys - On degenerations of the Seiberg-Witten monopoles and G₂ instantons
Robion Kirby - History of Low Dimension Topology
zhlédnutí 5KPřed 7 lety
Robion Kirby - History of Low Dimension Topology
Don Zagier - Modular forms, periods, and differential equations
zhlédnutí 9KPřed 7 lety
Don Zagier - Modular forms, periods, and differential equations
Robert McCann - A glimpse into the differential geometry and topology of optimal transportation
zhlédnutí 911Před 7 lety
Robert McCann - A glimpse into the differential geometry and topology of optimal transportation
Curtis McMullen - The Geometry of 3 Manifolds
zhlédnutí 6KPřed 8 lety
Curtis McMullen - The Geometry of 3 Manifolds
Wiles' Theorem on Modular Elliptic Curves Consequences - Henri Darmon
zhlédnutí 11KPřed 8 lety
Wiles' Theorem on Modular Elliptic Curves Consequences - Henri Darmon
Modularity of Mod 5 Representations - Karl Rubin
zhlédnutí 802Před 8 lety
Modularity of Mod 5 Representations - Karl Rubin
An Extension of Wiles' result - Fred Diamond
zhlédnutí 963Před 8 lety
An Extension of Wiles' result - Fred Diamond
Remarks on the History of Fermat's Last Theorem - Michael Rosen
zhlédnutí 2,4KPřed 8 lety
Remarks on the History of Fermat's Last Theorem - Michael Rosen
Non minimal Deformations (the Induction Step) - Ken Ribet
zhlédnutí 771Před 8 lety
Non minimal Deformations (the Induction Step) - Ken Ribet
Im so grateful that the sound quality is adequate.
God, the audio is horrible. Couldn't they have gotten a mike up there by him?
Must have been an exciting summer !
Benedict Gross is a great teacher <3, much respect
Absolutely beautiful lecture! I wish there were more of Tate’s talks available to watch online.
I have a proof that doesn’t fit inside the comment box
Thanks for this fantastic lecture!
Beal conjuncture proof czcams.com/video/1q_gTJSq1pc/video.htmlsi=eQd_85xaFupL-CMN
Fantastic lecture
Look at this link to see simple proof of FERMAT'S Last Theorem
I have fermats last theorem simple proof how to publish or how to verify how much that true.
You have a proof that doesn’t fit inside the comment box?
@@kilogods czcams.com/video/3fLbsKHIkNY/video.htmlsi=ACVFfFRW65BnfVHz
I was really hoping to get a lecture of Pascal's hexagrammum mysticum; particularly its relation to Pappus
13/8/2023. Ne pouvant sans cesse me répéter, veuillez vous reporter sur d'autres sites traitant du sujet où j'explique l'EQUATION UNIVERSELLE cachée et FACILE de FERMAT, enfin retrouvée, et la réfutation de sa conjecture. En plus, vous découvrirez que FERMAT s'est inspiré de PYTHAGORE puisque Z²= X² + Y² peut s'étendre à Zpuissance(N) = X² + Y² , +2 <= N < + infini .Depuis plus de 2.500 ans, ni Pythagore, ni aucuns mathématiciens n'ont vu cette merveille mathématique, cette pépite. Pour arriver à FERMAT, il faut avoir l'idée de passer par PYTHAGORE et non s'attaquer directement à la conjecture qui est la face NORD périlleuse de la montée vers la solution qui est difficile comme l'attestent les 129 pages de Monsieur WILES. La solution est tellement inattendue, courte et facile que PERSONNE depuis près de 4 siècles n'a pas trouvé l'astuce de départ du raisonnement de FERMAT, tout le monde cherchant une démonstration compliquée..
I like your smell....remember today 10th of August
4/8/2023. Afin de ne pas me répéter sans cesse, veuillez vous reporter sur d'autres sites traitant de ce sujet . Conjecture de FERMAT démontrée avec l'EQUATION UNIVERSELLE et sa jumelle , celle de Pythagore où Z² est égale et étendue à Zpuissance(N) avec 2 <= N < + infini. A noter que depuis plus de 2.500 ans ,ni Pythagore ni aucun mathématicien ne se sont aperçus de cette propriété et merveilleuse étendue de l'exposant à l'infini. Fermat étant un cas similaire. Pour (Z)puissance au cube, l'équation de Pythagore est jumelle de celle de FERMAT.
21/11/2023. EQUATION UNIVERSELLE cachée mais retrouvée le 5 juin 2022. Zpuissance(N+1) = Xpuissance(N) + Ypuissance(N) Solution de l'EQUATION en 4 lignes. Plus, inutile de continuer. Il y aura TOUJOURS une différence de ""+1"" entre la puissance de Z et celles de X et Y. D'où la conjecture Zpuissance(N) = Xpuissance(N) + Ypuissance(N) est IMPOSSIBLE quelles que soient les puissances jusqu'à l'infini.
He kinda sucks at lecturing
thanks for the post
Love this man’s book on elliptic curves but his lectures are even more precise thank you so much for upload !
I don't know why there are not many views of these wonderful lectures?
Probably because nobody knows what she's talking about
great lecture, but difficult to hear what he says. And bad video quality as well
Thanks , obviously , holonomies are important to me , I would agree .
she is always alive
This is the kind of mathematician that are unable to teach their own work in simple words. No wonder why people are scare with mathematics with such person teaching.
first off modular forms are not simple mathematical objects. second, the guy is presenting research which is well above graduate mathematics. 3rd he is presenting this piece of math to people who well and truly have the prerequisite knowledge to understand what he is talking about. you are like the person who wants quantum mechanics to become immediately transparent to them but have no foundational knowledge in newtonian mechanics.
@@abublahinocuckbloho4539 you are absolutely correct. A 5minute presentation of what are we presenting is the fundamental. Then I can five into further reading for more transparency. I'm a physicist and many researchers do this mistake of a quick intro of terminology before diving into the kernel.
جانم
💞💞
John Gave me another Full Life
I love math, and I love the way Tate talks about abelian varieties, it's as if it's completely obvious what's going on.
= THE GREAT! - THE GREATEST!!! Theorem of the 21st century! = !!!!!!!!!!!!!!!!!!!!! "- an equation of the form X**m + Y**n = Z**k , where m != n != k - any integer(unequal "!=") numbers greater than 2 , - INSOLVable! in integers". !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! /- open publication priority of 22/07/2022 / !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! /-Proven by me! minimum-less than 7-10 pp.
Ribet is a wonderfully clear and fluent speaker. Even his blackboard writing is clear! Amongst mathematicians talking about Fermat he seems to be quite unique in this respect.
So lovely mathematician!
as a highschooler i can tell you this makes very little sense. I'll be back here when i understand it
Thanks for sharing this !
Pretty cool stuff.
Thanks for this video lecture. Very enlightening.
ı cant read
That feeling when you realize the table of addition is the same as nim-addition... RIP, btw. He was one of the greatest mathematicians of all time and certainly my favourite one.
زیبا ترین زنی که هیچگاه ندیدمش و جهان هم بی بهره ماند
I proved on 09/14/2016 the ONLY POSSIBLE proof of the Great Fermat's Theorem (Fermata!). I can pronounce the formula for the proof of Fermath's great theorem: 1 - Fermath's great theorem NEVER! and nobody! NOT! HAS BEEN PROVEN !!! 2 - proven! THE ONLY POSSIBLE proof of Fermat's theorem 3 - Fermath's great theorem is proved universally-proven for all numbers 4 - Fermath's great theorem is proven in the requirements of himself! Fermata 1637 y. 5 - Fermath's great theorem proved in 2 pages of a notebook 6 - Fermath's great theorem is proved in the apparatus of Diophantus arithmetic 7 - the proof of the great Fermath theorem, as well as the formulation, is easy for a student of the 5th grade of the school to understand !!! 8 - Me! opened the GREAT! A GREAT Mystery! Fermath's theorem! (not "simple" - "mechanical" proof) !!!!- NO ONE! and NEVER! (except ME! .. of course!) and FOR NOTHING! NOT! will find a valid proof
August 1995
Absolutely amazing video!
مریم میرزاخانی برای ما زنان ایرانی هرگز نمی میرد و جزو بزرگترین الگو های زندگی ماست
Do the notes exist somewhere?
I have found them here :) www.google.com/url?sa=t&source=web&rct=j&url=wstein.org/edu/2010/582e/refs/washington-galois_cohomology.pdf&ved=2ahUKEwiGr57khpz3AhUS-aQKHcWmD5YQFnoECBMQAQ&usg=AOvVaw06CFxMhG5u2Yyk5nUkujPM
<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝)..
<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝).
I proved on 09/14/2016 the ONLY POSSIBLE proof of the Great Fermat's Theorem (Fermata!). I can pronounce the formula for the proof of Fermath's great theorem: 1 - Fermath's great theorem NEVER! and nobody! NOT! HAS BEEN PROVEN !!! 2 - proven! THE ONLY POSSIBLE proof of Fermat's theorem 3 - Fermath's great theorem is proved universally-proven for all numbers 4 - Fermath's great theorem is proven in the requirements of himself! Fermata 1637 y. 5 - Fermath's great theorem proved in 2 pages of a notebook 6 - Fermath's great theorem is proved in the apparatus of Diophantus arithmetic 7 - the proof of the great Fermath theorem, as well as the formulation, is easy for a student of the 5th grade of the school to understand !!! 8 - Me! opened the GREAT! A GREAT Mystery! Fermath's theorem! (not "simple" - "mechanical" proof) !!!!- NO ONE! and NEVER! (except ME! .. of course!) and FOR NOTHING! NOT! will find a valid proof
<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝)
When did Ribet deliver this talk? He looks young enough that it might have been right after Wiles's proof was announced. He speaks of the Taniyama-Shimura conjecture, which has for twenty years (since the proof of Wiles and others) been known as the modularity theorem.
Oh she,s death😰😔😢😢😢😢😭😭
Thank you professor , amazing lecture series I feel honored to be following them
Thank you professor
She was elected from God to be in God's team to do a better job in Heaven . We came from God and will go back to .she is in heaven .she lives for ever