Video

Thank You

Its wrong, because I= 1/12 bh3

its not correct if axis that you are going to calculate inertia upside of your figure the formula I= Ic-A.d^2 its downside of figure the formula I=Ic+A.d2 okay lets calculate for this example first Ic=bh^3/12 u know, 150*10^3/12 = 12.500 Now lets try to calculate this answer from another way . i.pinimg.com/originals/21/71/c7/2171c7dd7b545d4b762f34e5e5be06c2.gif I=bh^3/3 (its for axis that tangent rectangles down edge.) I=150*10^3/3 == 50.000 IC= I - A.d^2 == 50,000 -(150*10)5^2) Ic = 50.000 - (1500)*(25) Ic=50.000-37.500 Ic = 12500 Now as you can see when axis is upside, the formula --- Ad^2 downside the formula ++Ad^2

Sir I like u'r video, can u please make a tutorial on how you do it?

hello mr. would you mind if u send me your email i need some help from your research area in physical modelling of the rolling part using abaqus and some other questions...

hello,Mr Anup Pandkar.I have read your article. I havesome problems in it. Would you please send me a your Inp file? Thank you, my email address is dongll92@163.com

What is the name of this channel?

Hello, Mr Anup Pandkar. I´m impressed by you work. It´s very interesting. I would like to contact you by email to request your help and advise about how to setting up abaqus to perform this simulation. Thanks.

Thank you very much, the explanation was clear and understandable.

Thank you sir

Amazing work sir, How do I carry out rotating bending fatigue test on Abaqus??

You're awesome man, I wish you can be my Professor!!

Nice series of lectures Anup

MOI of that I section was just superb, less time consuming and simple. Thanks (Y)

i like this lecture.... it was a great lecture for MOI and PAT.

Sir I have a problem ...as the moment of inertia of an object is quantity expressing a body's tendency to resist angular acceleration... If i am right here then moment of inertia should be find out for a body which are in rotation.... But you took an example which haven't angular acceleration... Please clear my doubt if any one know

Thank u sir for this video

Wonderful sir, cleared the concept.

Very nice video, what if the body is consisted by 2 different materials? an i beam which the top and bottom flanches are from one kind of wood and the rest is from an other , is there a way to calculate the bending stress of this member? also a way to calculate the shear stress that happens on the glue bonding them together?

Thanks a lot sir ..... from faridabad .....

Bravo... this made things simply easier... Thankyou

thank you sooo much :D

Sir Unit of Moment of interia is m^4 ?? How its possible??

Awesome job!!! This was the only concept i was struggling with for my 2nd deformable bodies exam and these three videos made it so clear. THANKS!!!!!

sir please upload video on perpendicular axis theorem

nice videos

thanks that was a good lecture

God bless you sir for such a wonderful explanation

Thanks a lot

THANKS BRO. best video in the CZcams about 'Moment of Inertia' and 'Parallel axis theo. and their applications ..

thanks a lot , bro for great explaination ..

nice explanation but cameramen keep moving camera is really annoying

where is the mass of the body at (in the final term) ? i must have learned it another way maybe .. great explanation by the way

thanks for this video n the before one

thank you very much .

Thank you very much very helpful.

thanks sir...

extremely helpful Anup.

very clear

Best video in the CZcams of 'Moment of Inertia' and 'Parallel axis theorem'. Thanks a lot

nice lecture

wow very nice explanation

In example 2, we should subtract solid and smaller square is solid too, Smaller square should not be hollow. Correct me if I am wrong

Very well explained!! Thanks a lot!

Great explanation!!!!

how did u get 13.75 ??

good work bro. i like it & Thank you so much.

Anup, Could you fix your second half of the parallel axis theorem? It should read bh3 not bh2. Beside, the explanation is awesome.

100thanks

Good woork, would you like to send the tutorial or inp file, my email is cheikensmm@gmail.com Thank you