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[ With Logarithms, first always calculate the valid domains ] In any log_a(b), we should have b > 0, and a > 0 and a != 1. Here, a is already 3. Thus, we just need to ensure that x + 1 > 0 and x - 1 > 0, which implies that x > 1. 3x^2 - 7x + 2 = 0, has two solutions x = 1/3, x = 2. Since x > 1, we only accept x = 2. In this case, if you approach the problem systematically, there is no need to check the solutions. Just satisfy as per the domain, because the operations involved don't produce any loss of information. In some other types of questions, where you would need to square somewhere, the sign information gets lost, and then in the end, you will need to keep back the solutions in the original equation and verify.

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You missed something. You have to plug the values back into the original equation and when you do that, 1/3 - 1 = -2/3 < 0. log of that is not defined so 1/3 is not a solution. 2 is the only one available.

Hello sir! how to make your own mathematical formula?

Thanks🎉

dam i am here from the clip of your HCF i thought that your channal had grown bigger but i feel very sad that it didnot happened that way but sure have a good luck

My teacher gave me this as homework and I didn't know what to do this helped a lot 😊

to say that was helpful would be a total understatement! now, after watching many videos, your video makes it real...I understand the purpose of this completely, only sampling 11 girl students is manageable! but honestly, how do we choose those 11 girls, is it a simple random, or do we just choose 11 girls, or what? thank you very much! so glad i found you!!

Wait, this is the required level for LBoro? "We normally expect applicants to have a minimum of grade 4/C in GCSE English Language and, for most courses, GCSE grade 4/C in Mathematics. " :v

only difference is i would do it log9 / log2

God knew I’d be too powerful, if I could learn math

Had a quick go, got eveything but the minus 1, reread the question 'shaded area'! Not just big hexagon. Suppose thats the nice part of a show that, you can spot your error quickly

Thank you

too easy, scaling by a factor p means the new length will be p times original length and the area of a regular hexagon is just 6 times the area of an equilateral triangle with the same side length. Do some addition, subtraction of the two areas and you get the result.

Harika bir anlatım

👍

thanks so much

This was sooo useful thank you

why not just factorise to get ( 5y-6)(y+2)

Thanks helped a lot 😁✅

this guy's so adorable

Tysm

I dont get the 1/2 ab part I rewached the ab part and completely missed the halfing part thank you!

25 mine before my test

Hi, u just worked out to be +25. How did it turn out to be -25 ?

you are a beautiful man

THANK YOU SO MUCH OH MY GOD LAST EXAM I COULDNT FOCUS BC OF THE BOY NEXT TO ME AND I GOT TOO OVERSTIMULATED TO ANSWER ONEOF THESE QUESTIONS BUT YOUVE MADE IT SO MUCH EASIER I LOVE YOU

I hope someone can reply to this. Please for the 2nd example uhm why is only 15 the highest factor

YES , HE IS BACK 🎉🎉👏🥰

yay he is back again 😆😆

HES BACK!!!

42 cm3

6 cm2 x 7 cm =42 cm3

7x3=21 21+21= 42 cm3

1/2 3 x4= 12/2= 6 6 cm2

a=1/2 wh

3 cm 4 cm 7 cm

math

legend, thx so much

Thanks🙏

can you do (x-7) (x-3) plss

Only one comment😂 good vid

This really helped (aside from the lack of self esteem at having done the wrong equation for 3+ hours). However I have one question. What happens with the 20 at the end? Is that just -2.0 for the y-intercept?

Thank you so much! Didn’t listen in the lesson and learnt it in 3 mins. Thank you so much!

I love this so much

Very helpful as I have my maths GCSE tomorrow

THX BRO very very helpfull

Thank you so much❤❤