Video

Thank you

1:33 ?

Lap top m pada raha yaha mobile ma na pada ja raha😂

Thanks sir simple of explanation

Best explanation❤❤❤❤.. One day your hard work pay for it.....🎉🎉🎉🎉

Thank you god😊😊😊

Why cant we take cos-1in part 1

Niceee❤

Very helpful, incredible explanation sir thanks so much 😊

👍

Sir do more vedio on miscellaneous problem of trigonometry

Try solving jee pyqs you will get more views

Love ur way of teaching sir...

Really good

Mera Lund kuch bhi samjh nhi aaya

Thiks 🎉🎉😊😊😊

Bahot bahot sukhriya sir ji, samjh hi nhi aa rha tha ye ques Thank you 💗💗

Amazing explanation sir...

Explanation is so good

sir can you plz tell how |z1|=r1 and |z2|=r2

taninverse 2 x /1-x square to tan inverse x for x greater than 1 sir isme 2taninverse x - π answer hai but iska exact reason kya hoga samaj nahi aaraha hai normally 2 taninverse x hona tha na

It is a pyq of 2015

Very helpful ☺️

sir is question ke vajah se ro raha tha mai , pr aapki video se 100% clear hogya, thankyouuuuuuuuuuuuuuu

Thank you sir

So underrated

Thanks

Kuch samajh me nahi aaya

Kyu likh sakte ho😢😢sir

Can we do it with kings property , as it is in my dys of kings property Kings property- replace F(x) by F(a+b-x) When it is given to integrate F(x) in a to b

I'm from Bangladesh, Thank you so much Sir. No one has explained it in as much detail as you have.

Copied and paste the que by sir

Sin(θ+π/4)=sinπ/4 se ans sahi ayega kya

Thank you very much sir

Thanku❤❤

Youre good

That was really helpful🙂❤❤

🙏🙏

Tq so much sir 🙏

Bhai 2k2 - 3k -2 = 0 2k2-4K+k-2= 0 2k2-4K+k-2=0 Kasa hua

Thanks

Sir, without series expansion and l' hospital, nahi kiya jaa sakta kya?

Which tablet you have

Tanx/2=1/2 not 2

If we evaluate the indefinte integral in this question then Why did you substituted x = alpha (cos theta)^2 + beeta (sin theta)^2 ❓❓❓❓❓❓❓❓❓❓❓❓❓❓❓❓ In some books the answer of the indefinite integral is given as ---> __ __ | (x-alpha) | 2 Arc sin | ------------------------ | | (Beeta - alpha) | ‾‾ ‾‾ I did it by substituting ( x - alpha ) ( beeta - x ) = __ ( __ __ 2 ( | ( alpha - beeta ) | ( | ------------------------- | ➖ ( | 2 | ( ‾‾ ‾‾ ‾‾ __ __ __ __ __ 2 ) { | ( alpha + beeta ) | } ) { x - | ----------------------- | } ) { | 2 | } ) ‾‾ ‾‾ ‾‾ ‾‾ ) ‾‾ And I took -----> __ __ __ __ { | ( alpha + beeta ) | } { x - | ----------------------- | } = t { | 2 | } ‾‾ ‾‾ ‾‾ ‾‾ ===> ( x - alpha ) ( beeta - x ) = __ __ ( __ __ 2 ) ( | ( alpha - beeta ) | ) ( | ------------------------- | ➖ t ^ 2 ) ( | 2 | ) ( ‾‾ ‾‾ ) ‾‾ ‾‾ And dx = dt My answer came as ---> __ __ | 2 x - (alpha + beeta) | Arc sin | --------------------------- | | ( Alpha - beeta ) | ‾‾ ‾‾ Please tell why did u took x = alpha (cos theta)^2 + beeta (sin theta)^2 ❓❓❓❓❓❓❓❓❓❓❓❓❓❓

Love your videos it helps so muchh ❤❤

Good job sir

Thanks 😊

Thank you sir ❤

Tumcha aabhar sirji❤