Video

Special relativity problems are a lot of fun!

@@mtheorylaboratory Yes, i've been following you since the start of this year and you have helped me so much 8)

@@ashleyurbina1055 that’s awesome!

haha basis vector translation is weird!

haha thanks for watching! linear algebra was fun! :D

Awesome!

Using the correct radius in these types of problems is always confusing!

I always forget to boost the audio on my videos xD

Wow this was so long lol

Interesting topic, thanks for watching! :)

@@mtheorylaboratory indeed! I took Mathematical physics course last semester ,at first was not a fan it looked challenging but after practice it got easier although the test was quite difficult wish I discovered your channel earlier this year !

@@kareemosama5373 Oh cool, that sounds like fun! I’ll be taking that class soon too haha

@@mtheorylaboratory good luck 💞 all support for you

Haha thanks!

Hell yeah this is a cool problem!

Interesting observation! It does seem that it would be an exothermic reaction if the work is negative. Considering the airbag is expanding, it must be expending work to push outward!

@@mtheorylaboratory And what happens to the sodium? I understood sodium to be highly reactive at STP.

@@edmundorivera5825 It looks like airbags usually come with different chemicals like potassium nitride to have neutralize the sodium, cool!

@@mtheorylaboratory incredible science. I take care of burn patients. and although air bag burns are uncommon I wasn't aware of the mechanism. appreciate it.

@@edmundorivera5825 Oh that must be intense!

Joint Entrance Exam? Yeah I might cover similar topics that could be in it

​@@mtheorylaboratory Thank you Sir 🍎.. One thing which I want to tell you is that.. I am weak in physics and it would be good if you cover some of the topics of jee main exam perspective.. They ask high order question which is not that easy to solve. Right now I am studying Current Electricity (class 12 CBSE physics chapter)..

@@noblepower oh okay interesting.. if you have a specific question, maybe I can try it out.. but I am not great at engineering and circuits!

Thanks for watching!

This one was pretty funny xD

@@mtheorylaboratory i had my physics 2 final exam today and let me tell you, that was very useful

@@Sarah-vv8tz Excellent! Good job on the test you’re gonna ace it! Haha

Fun problem!

I’m tryna find dark matter :D

Btw , I am preparing for JEE

@@Zizz333 ohh that’s awesome good luck, it sounds very difficult! I want to take the certified ethical hacker exam someday! :)

Good question, this problem was very confusing for me. At 0:43 what we are doing is B[vB]=v which means we take matrix B multiplied by vector v (using the bases of B), just equals v. In other words: if B was just 1 1 * 2 = 2 Or if B was an identity matrix, you just get the v vector right back (as long as the v vector was constructed from i,j,k vectors)

Special relativity is crazy! :D

Haha right on!

no worries: sin(π-θ) = cos(θ) is actually just a trigonometric identity, it is not part of any triangle from the picture! to prove the identity, if we tried using θ=0 then we would get sin(π) = cos(0).. which means 1=1 this just means that in our problem, we can just swap out "sin(90-a)" with "cos(a)" because they're the same thing, that helps us to simplify the equation

Haha this problem was fun!

I did go very quickly through this one! To find carbon atoms: 1: divide given H atoms by avogadros number = # moles of H (11.96 mol) 2: C3H8 has 8 moles of H for every 3 moles of C 3: this allows us to set up a ratio: 8 moles H / 11.96 moles H = 3 moles C / ? moles C 4: now knowing the moles of C (4.485 moles) we can multiply again by avogadros number to find the number of atoms of C! To find the mass: 1. 11.96 moles of H * molar mass of H = 12.06g 2. 4.485 moles of C * molar mass of C = 53.87g 3. total mass is 65.93g

I think you’re right, I’ll try to explain this better in my next lecture video.. the biggest gap is using the wronskian to find the du’s: an interesting application of Kramer’s rule

I did think about that, but I had to make the decision to leave it: the idea is to be able to watch the whole video at a rapid speed, because that increases mathematical skill! I use these quick videos to practice too, like flash cards! Just 20 seconds to review each one, super helpful.. it does lower retention, but math is more important!

Right on, these ones are hard!

Thanks for watching! :)

Hmm, I believe that setting up two separate Kirchhoff loops would each have two different 11V batteries.. however it might be possible to combine these into a single 22V battery with only a single Kirchhoff loop!

Thanks for watching!

haha right on these problems are a little crazy

Haha thanks for watching!

This was a fun equation!

LOL oh no I usually cut that out but I missed this one!

Oh yes there is a video step-by-step in the description, I think the speed up version just looks funny to watch xD czcams.com/video/HIr9kXplkrQ/video.htmlsi=DZLF6tMeHpOCwkOK

Hey no worries I remember struggling with this one, our math teacher assigned it though so I’m not sure where it came from originally!

Excellent! This one is important!

Fun problem!

The only time h and k would have additional restrictions is if k was one of the pivots so it cannot be 0, or if you started dividing by h so it cannot be 0… but in your case we can rearrange the matrix to get an expression in the last 2 entries: h-9 = k-6 That equation allows us to find the values for h and k for no solution, one solution, and infinite solutions!

​​@@mtheorylaboratorywould it still be valid if I followed the steps in your video for my problem? I ended up with "y = k-6 / h-9" and followed how you got the solutions in the video. Trying to get these points i did bad on my last assignment 😅

@@user-el4su7tl6fexactly that would be the next step!

@@mtheorylaboratory thanks! Gonna submit it now its due at midnight 😩

@@user-el4su7tl6f you got this!

Haha sounds dangerous

@@mtheorylaboratory nah cuz I'm lazy

thanks for watching!

They got crazy books in the library!

If we simplify sin(A)cos(B), we can split it up and multiply each component by T(t) which is e^-i(E_n)t/ħ Ψ(x,t) = Ψ(x)T(t) Ψ(x,t) = A/2 [sin(2πx/2a)e^-i(E_2)t/ħ + sin(4πx/2a)e^-i(E_4)t/ħ] It appears that the energy levels possible are E2 and E4.. and it’s likely that the probabilities are 50-50 since they have the same coefficient (A/2) However, I’m not sure this is what they’re looking for!

Ok , and this question,can you solve this if you can solve in paper its better Q1/ Ψ(r, 0) = (1/√7)(2ψ100 + ψ210 + ψ211 + √3ψ21,-1) ,Calculate the value of the uncertainty (ΔLxΔLy) and explain in detail.

@@pretty.946 hmm I can try that one tomorrow, the reason I can’t really make a video is I’m not confident the answer is correct without official confirmation.. but I’ll try to link to an image if I can solve it, we’ll see!

Ok thank ,please try I have exam

@@pretty.946 It looks like this problem involves finding a series of integrals of the ladders of L... I think that might require some kind of computational program to solve this, or maybe not if this is supposed to be a simple example, but this seems like some higher level quantum mechanics that I haven't been able to cover yet :/

These are fun!

Awesome, lots of fun!

Haha right on, this was a fun problem!

How did u get Fda while having q there in the equation?

​@@wedyan_iol the net force equation on the left sets up: Fba = 2(Fda)cos38 on the right side, we know: Fda = k*qD*qA/L^2 because: F=kqq/r^2 then we can just substitute Fda into the previous equation Fba = 2(k*qD*qA/L^2)cos38 ultimately, since qA=q and we know all the other numbers Fba = 2[k*(3.2E-19)*q/(0.019)^2]cos38

That’s awesome, thank you!

Thank you for watching!

Nice! Haha yeah the DI method and the ‘chain rule for integrals’ make crazy math actually possible!