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Visions_Tutoring
Registrace 5. 03. 2018
This Channel will focus on studies ranging from math to physics and more. I may also include some interesting topics not taught in regular school curriculum.
Solving Absolute value equations
In this video I will talk about solving easy absolute value equations. I start off by explaining why absolute value always gives a positive result with and without a negative input. Then, I go and solve several equations to gain a better of understanding
zhlédnutí: 21
Video
The discriminant of a cubic equation
zhlédnutí 38Před dnem
In this video I will be talking about the cubic discriminant and how it defines the nature of the roots
Finding equations given roots of a polynomial
zhlédnutí 60Před dnem
In this video i will talk about finding the equation of a polynomial given its roots and I will show 2 examples where the solutions are all real and then all complex.
The Discriminant of a Quadratic equation
zhlédnutí 35Před 14 dny
In this video, I talk about the Discriminant of a Quadratic equation and go into a brief overview on how the roots of the quadratic behave when the discriminant is a specific value
Euler's method for solving quartic equations
zhlédnutí 51Před 14 dny
In this video, I talk about using Euler's method (Not to be confused with Euler's method on differential equations.) for solving polynomials of degree 4, namely, quartic equations. This is a brief overview on how we can find the solutions of a quartic equation using all three solutions to the resolvent cubic.
Quartic Formula derivation
zhlédnutí 112Před měsícem
This video will talk about deriving the formula for the polynomial of the fourth degree polynomial, using Descartes method of transforming a quartic into its depressed form, then forcing it into a product of two quadratics.
Quasi Symmetric Quartic Equation
zhlédnutí 108Před 8 měsíci
I will talk about how to solve this specific type of quartic and how to see if it is a symmetric quartic. I will go through deriving a formula for this type and solving an example for general use.
Solving Radical equations
zhlédnutí 21Před 9 měsíci
In this video, you will learn how to solve radical equations. This video is an introduction to solving basic-level radical equations. They will vary in difficulty. The next video will focus on cube root equations. One cube root radical equation was included at the very end.
Finding the number of a square root
zhlédnutí 16Před 10 měsíci
In this video I will show how to find the value of any square root by using a method very similar to long division.
Rational equations Algebra 2 (Intermediate examples)
zhlédnutí 14Před 11 měsíci
This video talks about Rational equations that are quite harder than those in my last video. These are more difficult to solve and simplify.
Logarithmic equations. Algebra 2
zhlédnutí 13Před 11 měsíci
This video will focus on solving intermediate level logarithmic equations where we have to solve for x and find some value for the equation.
Descartes Rule Of Signs For polynomials
zhlédnutí 23Před 11 měsíci
In this video i will show how to use Rene Descartes rule of signs and what our equation tells us even if we are missing a variable and what Descartes rule of signs tells us about the possible sign solutions we may get whether we can have positive or negative solutions and how many
Factoring Quartics (4th degree polynomials)
zhlédnutí 75Před 11 měsíci
I will talk about how to factor Fourth Degree polynomials by finding if it has two quadratic factors. This is known as the (two quadratic factors) Or also known as Double crisscross Method by bprp: czcams.com/video/4AS0tPluG_w/video.htmlsi=EWmIS5-ZEQIBPl5H .
Finding quadratic equation given points
zhlédnutí 37Před 11 měsíci
Here in this video you will learn how to find the equation of a general quadratic given three points by solving a system of equations with variables, a, b, and c.
Solving exponential equations using logs and natural logs
zhlédnutí 42Před rokem
I will talk about how to solve exponential equations using Logarithms and how to solve them when they have different bases i go through several examples ranging from easy to intermediate examples
Solving exponential equations with same bases
zhlédnutí 27Před rokem
Solving exponential equations with same bases
Systems of equations two variables Cramer's Rule
zhlédnutí 5Před rokem
Systems of equations two variables Cramer's Rule
System of equations two variable, elimination method
zhlédnutí 11Před rokem
System of equations two variable, elimination method
System of equations two variable Substitution method
zhlédnutí 26Před rokem
System of equations two variable Substitution method
Graphing Rational functions (easy examples)
zhlédnutí 64Před rokem
Graphing Rational functions (easy examples)
Solving quadratics using various methods
zhlédnutí 20Před rokem
Solving quadratics using various methods
Solving cubic equations using a quadratic
zhlédnutí 27Před rokem
Solving cubic equations using a quadratic
Finding an exponential equation given two points
zhlédnutí 35Před rokem
Finding an exponential equation given two points
Bisection method. Numerical analysis root finding algorithm
zhlédnutí 28Před rokem
Bisection method. Numerical analysis root finding algorithm
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Will the cubic always be factorable? Also does it matter the root I take?
The cubic wont always be factorable. And it doesn’t matter what root you use, but a cubic will either have 1 real root and 2 complex or 3 real roots which leads to complex cube roots. but either root of the cubic will still give the solution to the quartic
@@Visions_Tutoring Thanks for the response. With testing I think I found an explanation for why the cubic has 3 values. If you consider that the quartic has 4 factors: (x-x1)(x-x2)(x-x3)(x-x4), there are three ways to combine these in order to get two quadratics. I tried this with a cubic that had 3 rational solutions, and all 3 led to the different combinations of quadratics. Edit: I'm sure you knew this, but I thought it was cool to point out. Also, I've seen a false explanation once where someone said to take the "smallest root," rather than just saying "doesn't matter."
@@ta_ogboy9998 Well, It really doesn't matter which root of the cubic you use. They just lead to different combinations of quadratics. Though of course, if you use the complex solutions to the cubic, you will need to do extra work but any of the 3 roots will give a solution to the quartic by making two quadratics.
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Is there any method that output all 3 of the solutions of the cubic polynomial? And why did this output 1 anyways? What about the other 2 solutions? Why didn't this output them?
that's the problem with the cubic formula it gives only one solution, though you can find other 2 from this using primitive roots of unity for n=3
You just have to use the roots of unity for cubics, which is (-1+isqrt(3)) /2. If a cubic has three real distinct roots, then you will get a complex cube root, where you then have to use De Moivre's theorem. The reason this only gave one solution is because it outputs the real solution.
just show the formula please
The formula would not fit the screen; besides, it is a long, long formula that you may not want to use in practice.
@@Visions_TutoringDo it anyway.
okay check the recent video then
@@Visions_Tutoring Nice.
Cool
Wow awesome