Billy Woods - mathematics
Billy Woods - mathematics
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[ANT15] p-adic integers: a primer, and an application (part 1)
The p-adic integers are pretty easy to define, but it's far from obvious what the point of them is, or how we should even think about them. In this video, I describe them as a practical tool: a collection of number systems that are related to the usual integers Z, but where solving equations can be much easier. It would be nice if we could port these results back over from Z_p to Z, but that's a topic for another video...
zhlédnutí: 5 952

Video

[ANT14] Eisenstein polynomials and Strassmann's theorem, via a cubic example
zhlédnutí 884Před 2 lety
So far we've focused mostly on quadratic extensions, and have missed some interesting (although rather tricky and technical!) results as a consequence. Let's see a few of them.
[ANT13] Dedekind domains, integral closure, discriminants... and some other loose ends
zhlédnutí 1,5KPřed 2 lety
In this video, we see an example of how badly this theory can fail in a non-Dedekind domain, and so - regrettably - we finally break our vow of not learning what a Dedekind domain is.
[ANT12] Quadratic reciprocity and prime factorisation
zhlédnutí 960Před 2 lety
In this video, we finally put all the pieces together and see how quadratic reciprocity can help us to factorise primes in quadratic extensions of Z. ANT books: Marcus, "Number Fields"; Ireland and Rosen, "A Classical Introduction to Modern Number Theory"... Keith Conrad's notes: kconrad.math.uconn.edu/blurbs/gradnumthy/quadraticgrad.pdf
[ANT11] Quadratic Gauss sums
zhlédnutí 1,5KPřed 3 lety
Last video, we used the fact that √2 = ζ ζ⁻¹, for ζ an 8th root of unity, to tell us about the decomposition of rational primes in Z[√2]. In this video, we see that it is also possible to write √q as a sum of roots of unity for all *odd* primes q: in fact, we write down an explicit element τ whose square is ±q.
[ANT10] Prime decomposition in Z[√2]
zhlédnutí 1KPřed 3 lety
We return to our study of primes. We don't yet have a general method to find the primes of anything other than Z[i], and eventually, we'll want to know that; so let's start for now with the (relatively easy) example of Z[√2]. How can we tell when a (rational) prime splits, remains inert or ramifies after extension to Z[√2]? What difficulties present themselves? How far will these methods genera...
[ANT09b] The Diophantus chord method
zhlédnutí 965Před 3 lety
Cremona's tables: johncremona.github.io/ecdata/ Table for example 2: www.lmfdb.org/EllipticCurve/Q/576/c/3 Tables for example 3: www.lmfdb.org/EllipticCurve/Q/27/a/3 and www.lmfdb.org/EllipticCurve/Q/432/e/4 Table for the exercise: www.lmfdb.org/EllipticCurve/Q/1728/n/3
[ANT09] Stacking oranges
zhlédnutí 839Před 3 lety
In this video, we see how Pell's equation can be used to solve higher-order equations over the integers. We see another example of the importance of understanding which numbers are squares modulo each prime. The question was originally posed by Lucas: Nouvelles Annales de Mathématiques, série 2, tome 15 (1876), p144, question 1194: www.numdam.org/article/NAM_1876_2_15 144_1.pdf (in French) Meyl...
[ANT08b] Square triangular numbers
zhlédnutí 1,6KPřed 3 lety
Another application of Pell's equation.
[ANT08] Continued fractions, Pell's equation, and units of Z[√d]
zhlédnutí 5KPřed 3 lety
A brief detour into an unexpected kind of "approximation by rationals" algorithm allows us to easily solve Pell's equation (often by hand!), and hence calculate the units in Z[√d] for positive integers d.
[ANT07b] A closer view of log space
zhlédnutí 821Před 3 lety
[ANT07b] A closer view of log space
[ANT07] Units and logarithm space (+ bonus theorems)
zhlédnutí 1,3KPřed 3 lety
There are infinitely many units in Z[√2]. How can we write them down? How can we figure out their multiplicative structure? (Plus, now that we've come this far, a few theorems to make the link between this course and more traditional courses.)
[ANT06] Real and imaginary embeddings
zhlédnutí 1,5KPřed 3 lety
When we try to draw a real quadratic extension of Z in the complex plane, it collapses onto the real line - we don't get a lattice any more. We're going to prise it apart by drawing it on the real line in two different ways at once. We'll be able to recover a genuine notion of geometry, and we'll see how we can apply Minkowski's theorem to learn about arithmetic in these rings.
[ANT05] Minkowski's geometry of numbers
zhlédnutí 3,5KPřed 3 lety
Unsurprisingly, many of the pictures we've drawn are honest geometric objects, leaving them open to geometric attacks.
[ANT04] Counting ideal classes
zhlédnutí 2,8KPřed 3 lety
We don't always get unique factorisation. In those cases, can we measure how badly this uniqueness fails?
[ANT03] Ideal factorisation: recovering uniqueness
zhlédnutí 3KPřed 3 lety
[ANT03] Ideal factorisation: recovering uniqueness
[ANT02] Arithmetic in Z[i] and beyond
zhlédnutí 3,3KPřed 3 lety
[ANT02] Arithmetic in Z[i] and beyond
[ANT01] Algebraic number theory: an introduction, via Fermat's last theorem
zhlédnutí 11KPřed 3 lety
[ANT01] Algebraic number theory: an introduction, via Fermat's last theorem

Komentáře

  • @PRIMARYATIAS
    @PRIMARYATIAS Před 4 měsíci

    When part 2 ? 🙏

  • @omipial2084
    @omipial2084 Před 5 měsíci

    3:42

  • @omipial2084
    @omipial2084 Před 6 měsíci

    Is there any book/lecture note that is close to your approach? Please, inform, I need a written form.

    • @SBWielinga
      @SBWielinga Před 2 měsíci

      There is, I think, a perfect sequel to this series: Dino Lorenzini, An Invitation to Arithmetic Geometry. It's not much more difficult but fleshes out the logic (such as what's in this video: why Dedekind domains? Discriminants? Ideal class groups?) REALLY thoroughly; has copious examples like this video series; and it gets all the way up to proving the Riemann-Roch theorem! I do think it's best to also own Hartshorne's Algebraic Geometry at the same time though: just the first few pages make what's in Lorenzini's book feel like they have a solid context, and might make parts of it make more sense.

    • @omipial2084
      @omipial2084 Před 2 měsíci

      @@SBWielinga Thank you very much for your informative comment.

  • @NicolasMiari
    @NicolasMiari Před 7 měsíci

    The rational integers satisfy monic polynomials with integer coefficients of degree 1, e.g. x - 3 = 0, so the generalization to monic polynomials of higher degree for higher algebraic integers makes sense (if these linear polynomials were not monic, they're satisfied by non-integer, rationals numbers).

  • @nicholasparkin6054
    @nicholasparkin6054 Před 7 měsíci

    I Just came across this channel and it is fantastic! But I am a little worried that it may have stopped as this video was uploaded a year ago. Are you still going @billy_maths? I really hope that you are.

  • @ericzenk4404
    @ericzenk4404 Před 7 měsíci

    I looked up Frohlich and Tayler and it looks interesting. do you recommend any particular books on algebraic number theory?

  • @MP-fv4mr
    @MP-fv4mr Před 7 měsíci

    Amazing! ❤

  • @ericzenk4404
    @ericzenk4404 Před 7 měsíci

    excellent video. I think I read a section about this (20 years ago) in Hardy and Wright but it didn't sink in.

  • @ericzenk4404
    @ericzenk4404 Před 7 měsíci

    this reminds me of pictures people use of the upper half plane of C (as a model for hyperbolic geometry).

  • @ericzenk4404
    @ericzenk4404 Před 7 měsíci

    I really appreciate the concrete approach and pacing. You explain enough that I can understand (maybe after pausing, rewinding in spots) but overall it is very clear and interesting.

  • @ericzenk4404
    @ericzenk4404 Před 7 měsíci

    I really enjoy the videos. I watched part 15 (on p-adic arithmetic), part 1 and part 2. These are well thought out, and challenging (I have had to stop, rewind, ...) but if I try I can learn ANT. It would be good to see part 16 (local to global I imagine). p.s. I am a mathematician who hasn't studied ANT.

  • @thetotalfunction7736
    @thetotalfunction7736 Před 8 měsíci

    Brilliant!

  • @thetotalfunction7736
    @thetotalfunction7736 Před 8 měsíci

    This video should be recommended to anyone who watched Stand-Up Matt's and lacked the context.

  • @georgeorourke7156
    @georgeorourke7156 Před 8 měsíci

    2.9K views and only 108 likes ??? It's a disgrace. It should be 2.9K likes....people don't know how to appreciate real quality work.

  • @georgeorourke7156
    @georgeorourke7156 Před 8 měsíci

    Excelente lecture. Many things contribute to a first class lecture: the graphics, the tempo of the presentation, the explanations, the tone of voice and a love of the subject. You have all these qualities. I just stumbled upin you lecture as I wanted to learn some about p-adic numbers. I'm sure glad I found your site. Please keep up the great work.

  • @greenland8376
    @greenland8376 Před 8 měsíci

    Dear Billy Woods, this lecture is phenomenal. I am so glad to have discovered your channel. I hope there to see much more of you in the future.

  • @ilyanebraij8495
    @ilyanebraij8495 Před 9 měsíci

    thank you so much for this serie of videos , tne content is really really enriching that's the least that I can say. I love how I see things totally differently now , known concepts make much more sense now , if you can do a video about Q_p and the projective line it would be marvelous. Again thanks a lot!!!

  • @ilyanebraij8495
    @ilyanebraij8495 Před 9 měsíci

    thank you so mcuh for this video series , this was really what I needed

  • @lachlanperrier2851
    @lachlanperrier2851 Před 9 měsíci

    Wait a minute Is 2s complement just a p adic representation?

    • @billy_maths
      @billy_maths Před 9 měsíci

      Yep, it's a (truncated) 2-adic representation!

    • @tanvach
      @tanvach Před 9 měsíci

      I also just learnt about this connect recently. Since 2s complement representation is a bit more familiar, I wish p-adic introduction materials start with this and expand to other primes.

    • @ingiford175
      @ingiford175 Před 5 měsíci

      @@billy_maths And because of how it is truncated, it only can hold integers.

  • @kilogods
    @kilogods Před 9 měsíci

    Absolutely amazing video

  • @NicolasMiari
    @NicolasMiari Před 9 měsíci

    15:26 "In an ideal world..." I see what you did there! 😂

    • @billy_maths
      @billy_maths Před 9 měsíci

      I'm glad someone appreciates me! 😮‍💨

  • @jonatansvensson8346
    @jonatansvensson8346 Před 9 měsíci

    Very well presented, thanks!

  • @oneofthechannelsofalltime
    @oneofthechannelsofalltime Před 10 měsíci

    Yeah, a buddy of mine told me about them.Tell you what, I'm never visiting Germany or Europe.

  • @mrsarkar6933
    @mrsarkar6933 Před 10 měsíci

    Excellent 👌 Can you make a video of the construction of p-adic integers Z_p algebraic way ? For example, we want to solve the equation $x^2=a$ (mod p) and then continue to divide by p and find successive solutions to get the p-adic integers.

  • @rishonfernandes7976
    @rishonfernandes7976 Před 11 měsíci

    How do you show p1p2 = (2), p3p4 = (3), ...?

  • @cafeinst
    @cafeinst Před rokem

    I appreciate your videos so far. I am not finished yet. I have tried to read books on algebraic number theory, but could never really appreciate them because they do not provide good examples or motivation. Your videos do this.

  • @cafeinst
    @cafeinst Před rokem

    I am used to seeing the Legendre symbol with parentheses, not square brackets.

  • @thomuzmphela
    @thomuzmphela Před rokem

    This whole playlist was most illuminating, thank you

  • @thomuzmphela
    @thomuzmphela Před rokem

    impeccable presentation

  • @IRanamans
    @IRanamans Před rokem

    I love the video! I have a question, so my friend figured that any odd squared number minus one divided by 8 equals a Triangular number. I wanted to know if there is any equation could lead us to this pattern without just guessing randomly.

    • @IRanamans
      @IRanamans Před rokem

      I tried to prove it but I'm not very sure about my answer. And I couldn’t ask my math teacher. So i squared (2k+1) giving me an odd squared number(n), n=4k^2+4k+1. Subtracting 1 from both sides, we get n - 1 = 4k^2+4k. - Factoring out 4k from the we get n - 1 = 4k(k + 1). Since k and k + 1 are consecutive integers, one of them is even. Therefore, 4k(k + 1) is divisible by 8. Im not sure ab the last step^^^

    • @foli9092
      @foli9092 Před rokem

      @@IRanamans Yes, you are correct. In the last step, just rewrite it as (2k+1)^2-1=4k(k+1)/8=k(k+1)/2 and since k is an integer this is exactly the form of the k'th triangular number.

  • @fredpim11
    @fredpim11 Před rokem

    your videos are fantastic ! thank you

  • @ervingegprifti2612
    @ervingegprifti2612 Před rokem

    This is a rare unique explanation. Thank you!

  • @omargaber3122
    @omargaber3122 Před rokem

    This explanation is wonderful and you are genius

  • @silversky216
    @silversky216 Před rokem

    Hello sir. I need to prove the following result "Class number 1 implies and implied by PID". What are the prerequisites from Alg. Number Theory to prove this result?

    • @cafeinst
      @cafeinst Před rokem

      True almost by definition

    • @silversky216
      @silversky216 Před rokem

      @@cafeinst Hi, thanks for your reply but I have already figured it out😊😊😊😊

  • @Bermatematika
    @Bermatematika Před rokem

    In 12:50 when you write gcd(2x,z) this gcd should be computed in the Gaussian integer. So to be careful one need to mention first that for integers a,b , the gcd(a,b) as integer is also a gcd for a and b as Gaussian integers.

  • @Bermatematika
    @Bermatematika Před rokem

    Just to be a little pedantic, doesn't in general ring, two elements are relatively prime if their gcd is unit?

  • @danpucci1
    @danpucci1 Před rokem

    The best explanations on this subject I've ever found!

  • @aweebthatlovesmath4220

    I'm really glad that i find your channel. your video quality is very good keep it up!!

  • @gtjacobs
    @gtjacobs Před rokem

    This video is wonderful. Thank you!

  • @shortnotes-bds2621
    @shortnotes-bds2621 Před rokem

    Can you make such amazing playlist on algebraic geometry too? I am having a hard time with Hartshorne

    • @billy_maths
      @billy_maths Před rokem

      Thank you for the very kind comment! I don't think I'll get around to that any time soon, but to my mind, Ravi Vakil has already done a far better job than I ever could: czcams.com/channels/y3u23mZE4TyW88yr6JLx9A.html

  • @mrl9418
    @mrl9418 Před rokem

    I had the completely unfounded notion this was an old one, so there must be a follow-up. Uploaded 7h ago 😐

    • @billy_maths
      @billy_maths Před rokem

      Oops! Follow-up very soon, I hope. ;)

  • @t0lgi019
    @t0lgi019 Před rokem

    I've been secretly wishing for you to do a video introduction series to p-adics. Very happy to see you actually doing it :) Keep the good work up 👍

    • @billy_maths
      @billy_maths Před rokem

      Thank you! More p-adic videos to come soon, I hope :)

  • @bineapple
    @bineapple Před rokem

    Thank you for sharing! I have a question, on 20:45 why can you assume that unit to be 1?

    • @billy_maths
      @billy_maths Před rokem

      Good question - I definitely skimmed over this detail! I seem to remember it's a tricky calculation involving modular arithmetic mod 9 (or equivalently mod π⁴), but I don't remember exactly how it goes. I'll have a think and see if I can get back to you!

    • @billy_maths
      @billy_maths Před rokem

      Okay, I think I've got it. I'll write γ' = uc³ for some unknown unit u in Z[ω]. (There are only 6 units in Z[ω], so we have u = ±1, ±ω or ±ω².) Remember that α and γ are both divisible by π, and notice that y = (γ - α)/π, which we can rewrite as γ' - α/π. Now, since α is divisible by lots of factors of 3, so is α/π, and so we get y = γ' (mod 3), so that y = uc³ (mod 3). (This "mod 3" is actually modular arithmetic *inside Z[ω]*, i.e. arithmetic in the quotient ring Z[ω]/3Z[ω]. I wasn't assuming viewers would be familiar with this, which is probably why I omitted this detail!) Now, y is an integer and (by an assumption we made a few minutes earlier) is not divisible by 3, so either y = 1 (mod 3) or y = -1 (mod 3). Putting these together, we get ±1 = uc³ (mod 3). Write c = d + eω for some integers d and e: then c³ = d³ + e³ (mod 3), and again, as d³ + e³ is an integer, it must be 0, 1 or -1 (mod 3). Plugging this into the above equation, we get either ±1 = 0 (mod 3) (a contradiction) or ±1 = ±u (mod 3), which we can write slightly more neatly as 1 = u² (mod 3). Now we can just check the three cases directly: if u = ±ω, then 1 = ω² (mod 3), so ω²π = 0 mod 3, so π = 0 (mod 3), i.e. π is divisible by 3. But this can't be true: N(π) = 3 and N(3) = 9. Similarly u can't be ±ω². So it must have been ±1. (And if it's -1, then rewrite γ' = -1*c³ as 1*(-c)³.)

  • @Thomas-cat
    @Thomas-cat Před 2 lety

    I love your style !! very great diagrams !

  • @jessevanderbeek9243
    @jessevanderbeek9243 Před 2 lety

    Excellent playlist! What software and tablet setup do you use to make these?

    • @billy_maths
      @billy_maths Před rokem

      Thank you! In this video, I think I used my Microsoft Surface + pen, OneNote for handwriting, OBS to record video, Audacity to record audio, and OpenShot to edit. In my later videos, I'm mostly using Cavalry for the 2D animation and Lightworks for the editing. :)

  • @omargaber3122
    @omargaber3122 Před 2 lety

    amazing