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PhysicsMania-Mohit Gupta [IIT BHU]
India
Registrace 29. 03. 2020
Video
Graphs of Motion in One Dimension|Class 11|Class 12|NEET|JEE
zhlédnutí 92Před 2 měsíci
Graphs of Motion in One Dimension|Class 11|Class 12|NEET|JEE
Self Induction and Mutual Induction|CLASS 11|CLASS 12|JEE|NEET
zhlédnutí 57Před 2 měsíci
Self Induction and Mutual Induction|CLASS 11|CLASS 12|JEE|NEET
Charging and discharging of Inductor|Class 11|Class 12|JEE|NEET
zhlédnutí 70Před 3 měsíci
Charging and discharging of Inductor|Class 11|Class 12|JEE|NEET
Current induced in Vertical Conducting frame|CLASS 11|CLASS 12|JEE|NEET
zhlédnutí 30Před 3 měsíci
Current induced in Vertical Conducting frame|CLASS 11|CLASS 12|JEE|NEET
Projectile Motion Introduction|JEE|NEET|CLASS 11|CLASS 12
zhlédnutí 43Před 3 měsíci
Projectile Motion Introduction|JEE|NEET|CLASS 11|CLASS 12
Moving coil galvanometer|NEET|JEE|CLASS 11|CLASS 12
zhlédnutí 61Před 3 měsíci
Moving coil galvanometer|NEET|JEE|CLASS 11|CLASS 12
What is cyclotron|JEE|NEET|2024|Class 11|Class 12
zhlédnutí 43Před 3 měsíci
What is cyclotron|JEE|NEET|2024|Class 11|Class 12
Equivalent Resistance in Symmetrical circuits|CLASS 12|CLASS 11|JEE|NEET
zhlédnutí 24Před 3 měsíci
Equivalent Resistance in Symmetrical circuits|CLASS 12|CLASS 11|JEE|NEET
Charging of a capacitor|NEET|JEE|PHYSICS CLASS 12
zhlédnutí 34Před 3 měsíci
Charging of a capacitor|NEET|JEE|PHYSICS CLASS 12
What is Potentiometer|JEE|NEET|CLASS 11|CLASS 12
zhlédnutí 33Před 3 měsíci
What is Potentiometer|JEE|NEET|CLASS 11|CLASS 12
Motion under Gravity|JEE| NEET| CLASS 11
zhlédnutí 402Před 3 měsíci
Motion under Gravity|JEE| NEET| CLASS 11
Types of Motion|Class 11 Physics | IITJEE | NEET
zhlédnutí 207Před 3 měsíci
Types of Motion|Class 11 Physics | IITJEE | NEET
Instantaneous Velocity and Acceleration|Neet|JEE|Class 12
zhlédnutí 32Před 3 měsíci
Instantaneous Velocity and Acceleration|Neet|JEE|Class 12
Differentiation Needed for Physics |IIT-JEE| NEET
zhlédnutí 70Před 3 měsíci
Differentiation Needed for Physics |IIT-JEE| NEET
Swimmer River Concept-Relative Velocity Physics | Easiest Method
zhlédnutí 92Před 4 měsíci
Swimmer River Concept-Relative Velocity Physics | Easiest Method
Rain Man Concept Physics-Easiest Explanation Ever by IITian Mohit Sir
zhlédnutí 73Před 4 měsíci
Rain Man Concept Physics-Easiest Explanation Ever by IITian Mohit Sir
Electrostatics-17 | NEET JEE PYQs Part 2 | IITJEE-NEET
zhlédnutí 113Před 5 měsíci
Electrostatics-17 | NEET JEE PYQs Part 2 | IITJEE-NEET
Electrostatics-16 | NEET JEE PYQs Part 1 | IITJEE-NEET
zhlédnutí 66Před 5 měsíci
Electrostatics-16 | NEET JEE PYQs Part 1 | IITJEE-NEET
Physics By Mohit Sir Bathinda | Anhad Thukral 99.86%ile in JEE MAINS
zhlédnutí 149Před 5 měsíci
Physics By Mohit Sir Bathinda | Anhad Thukral 99.86%ile in JEE MAINS
Electrostatics-15 | Electric Dipole | IITJEE-NEET
zhlédnutí 157Před 5 měsíci
Electrostatics-15 | Electric Dipole | IITJEE-NEET
Electrostatics-14 | Electrostatic Potential Energy | IITJEE-NEET
zhlédnutí 47Před 5 měsíci
Electrostatics-14 | Electrostatic Potential Energy | IITJEE-NEET
Electrostatics-13 | Conducting Plates | IITJEE-NEET
zhlédnutí 87Před 5 měsíci
Electrostatics-13 | Conducting Plates | IITJEE-NEET
Electrostatics-12 | Earthing | Connecting Two Conductors | IITJEE-NEET
zhlédnutí 78Před 5 měsíci
Electrostatics-12 | Earthing | Connecting Two Conductors | IITJEE-NEET
Electrostatics-11 Cavity Inside Conductor | IITJEE-NEET
zhlédnutí 76Před 5 měsíci
Electrostatics-11 Cavity Inside Conductor | IITJEE-NEET
Electrostatics-10 | Calculation of Potential
zhlédnutí 91Před 5 měsíci
Electrostatics-10 | Calculation of Potential
Electrostatics-8 | Gauss Law Application | Calculation of Fields
zhlédnutí 83Před 6 měsíci
Electrostatics-8 | Gauss Law Application | Calculation of Fields
these videos are really underrated ....your way of explaining is very good .......thanks for uploading such great videos
@@aushrathun8522 Thankyou so much
C option 😮
Sir c option
C option 👍🏻
C option
C ans hai
Nicee
Conservation of angular momentum
C
👌🏻👌🏻
Sir bahut acha background music Or ye vala celebration hamesha yaad rhega ❤🥺
Aaj tak bas physics books main ye dekha hai. Nice to see live demonstration!
Best teacher ❤❤
Thankyou
Gym change kro paaji, may be you find some good trainers in other gym😂
😂😂
Woowww😅
✌️✌️😇😇
Pascal law pressure same on both side, more area more force needed for same pressure sir aap toh shayad moti syringe ke saath bhi jeet jaate🤣
Correct
great explanation!
Sir hamare batch mai kyu nhi kiye the 😢
Sir ap to actor bhi bohot ache nikale❤ Soft ball se hath pe lagne ki zabardast acting kari😂
Whats time complexity sir?
pls..can you provide the list of questions..which were asked in a deshaw..plssss..if anybody knows..kindly help..
Pascal law
sum 1 considering all coin wala sentence samajh nhe aya for including and excluding
B
I usually don't comment but the way you explained has compelled me to write. Thank you bro.
@@qjawed9654 Thankyou so much :)
It is important to tell that you guys before seeing the cards have made out with the logic that will help one of you to figure out the 5th card ; the prediction of 5th Card is Totally based on the order in which you distribute cards.
Actually here the idea of flipping creates a confusion Of tossing in the sense that the outcome would either be tails or heads but what it meant was to invert the coins Thats why was unable to understand the puzzle.
Ist law lga hai kyuki ball motion me thi toh jab fenkha gya ball ko toh wo motion me hi rehna chahti hai
Second law
Great explanation
You deserve more subscribers thank you sir🎉❤
Thankyou so much :)
💪💪💪🤜🤛
Sirr finally shirtless photo🔥 Bohot badhiya body hai sir🔥💯
🔥🔥
Not in syllabus of jee and neet
jitne baar repeat hua usko aapne 720 se divide kyu kia...wo to minus hona chahiye
kya racist ques hai
No need for vector arr we can directly increment noOfLetterSmaller just by putting condition in 2nd loop. Below is the code int mod = 1000003; int fact(int n) { if (n == 0) return 1; else return ( n * fact(n - 1)) % mod; } int Solution::findRank(string A) { int n = A.size(); int smallChar; int res = 0; for(int i=0;i<n-1;i++){ smallChar = 0; for(int j=i+1;j<n;j++){ if(A[j] < A[i]) smallChar++; } res += (smallChar * fact(n-i-1)) % mod; } return (res+1) % mod; }
bhaiya main mein direct call krun function ko ya usse pehle bhi kuch krna hai
This was my today's interview question after don't getting the answer I am here
@@user-bs7rb5fz8t I hope its clear now?
sir control😂😂
U deserve more subscriber.
Nice one sir
thats why sir weight is increasing 😂
Great explanation