Video

outstanding sir ....hats off

You are doing gods work brother thank you

❤

Thanks from India 🇮🇳🫶

I don't know if you are reading the comments right now, but if you are, I must say that you have a great channel. I am a physics Olympian and sometimes math can be difficult for me. I came across your channel on reddit while looking for a good resource on differential equations, your videos are very explanatory and the integrals you solved were the ones I couldn't solve and they helped me a lot in this regard. You uploaded your last video 1 year ago, it is very sad that a channel like yours has few views. I know it is impertinent to say this, but please continue uploading videos. I am sure you will be trending one day, because you deserve it. Have a nice day

gracias por la magnifica explicación ,saludos desde México

You can do the same thing with hyperbolic functions using e^x=cosh(x)+sinh(x). Instead of matching the real and imaginary components in the equality, you match the even and odd components.

Very very clear! And the right speed: I can follow, and it is not too slow! And you convey your fascination for math! Just great!

Thanks for the new and simple way of finding INTEGRATION BY PARTS .....!!!

Asombroso!

As always, a wonderful video. Fractional derivatives are a fascinating concept that I hadn't thought of before. It was also enormously helpful to link it with the gamma function, which I only learned about yesterday.

It has truly brightened my day to stumble onto this channel. After a long search, I came upon this extremely clear and thorough description of the gamma function. Continue doing what you're doing; you are a great instructor.

Loved and subscribed !!!!

Mr perfect ❤

Thank you, doing my physics degree with many gap years from my A levels. Your channel is very hlpful

vine con mi mono choro, robale todo

Y only say that tan(x)=sin(x)/cos(x) Then say u=cos(x) So -du=sin(x)dx So the resultant integral was -∫(ln(u)/u)du With the simple substitution v=ln(u) and dv=du/u and working it the result is ln²(u)/2+c=ln²(cos(x))/2+c

Probably is not the best method, but I use x=tan⁴(θ), dx=4tan³(θ)sec²(θ)dθ So I get the integral of tan⁵(θ)dθ And is not bad with the identity of tan²(θ)=sec²(θ)-1 The integral give me tan⁴(θ)-2tan²(θ)+4ln|sec(θ)|+c tan⁴(θ)=x 2tan²(θ)=2√(x) 4ln|sec(θ)|=4ln|√(1+√(x))|=2ln|1+√(x)|=2ln(1+√(x)) So x-2√(x)+2ln(1+√(x))+c

Easier to understand, thank you so much❤

Γ(z)= ∫₀ ᪲ tᶻ⁻¹ e⁻ᵗ dt

The clarity of your whiteboard script is very helpful.

Interesting. I wonder what real applicaions are on the horizon with fractional derivatives.

thank you very much! ive been struggling on the chain rule in my course

tysm i was about to kms over this

this was awesome and very helpful thanks

Thanks from Afghanistan

I want you as my teacher lol

Great work! Easy to understand

of course much simpler and clear path

extremely helpful video, thank you so much!

why do we split the boundary as top and bottom and not left and right?

the shortcuts part in the end is very nice

Do Lagrange multipliers work for this?

amazing

how is root 2 the outer function in the very first example

👍👍

Thank you man, this video is the only one i've seen about this topic that is very in depth and straight to the the point.

I love how he teach despite being outside with two sun just for us to learn<3 btw I'm a BS mathematics student and I thank u for making my college bearable

Beautiful explanation. Love the side-by-side symmetric demonstration. However, it would be nice to see how reduction of order is used to get those natural logs in the solution set.

Very complicated

to derive the identities for tan I imagine you just divide the sin identity by the cos identity?

Wow! Thanks mate the best articulated explanation of the Gamma Function I have found, yes I viewed many before I found yours, subscribed!!

how do i find g(x) if i have a third order DE? the DE im given is x^3 y''' + x^2 y'' = x^3. i take this class in the fall and am just trying to solve a question a friend gave me, lol

Ty man.

very useful👏

love the quality of the vid fam. 4k is a plus no longer have to squint plus you cut my studying to like 5 mins. basically win win

Fantastic explanation!

Man what a lifesaver. I love how you teach, not sure why but it all clicks very fast when you explain it.

Gamma of (p/q) = ? such that p and q are natural number.

Maths genius🎉