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Mark Taylor
United States
Registrace 16. 03. 2010
CHM1025 WS10 Q8
Given the following data:
2 O3 (g) → 3 O2 (g) ΔH = -427 kJ
O2 (g) → 2 O (g) ΔH = +495 kJ
NO (g) + O3 (g) → NO2 (g) + O2 (g) ΔH = -199 kJ
Calculate H for the following reaction
NO (g) + O2 (g) → NO2 (g) + O (g) ΔH = ?
2 O3 (g) → 3 O2 (g) ΔH = -427 kJ
O2 (g) → 2 O (g) ΔH = +495 kJ
NO (g) + O3 (g) → NO2 (g) + O2 (g) ΔH = -199 kJ
Calculate H for the following reaction
NO (g) + O2 (g) → NO2 (g) + O (g) ΔH = ?
zhlédnutí: 15
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CHM1025 WS10 Q6
zhlédnutí 13Před dnem
If 125 J of heat energy is applied to a block of silver (Specific Heat Capacity = .24 J/g ºC) weighing 29.3 g, by how many degrees will the temperature of the silver increase?
CHM1025 WS10 Q5
zhlédnutí 20Před dnem
If 69.5 kJ of heat is applied to a 1012-g block of metal, the temperature of the metal increases by 11.4ºC. Calculate the specific heat capacity of the metal in J/g ºC.
CHM1025 WS09 Q4
zhlédnutí 5Před dnem
Using the following unbalanced equation, a) calculate the maximum grams of copper you could produce when starting with 17.0 g of zinc and excess Cu2(SO4)3. Zn(s) Cu2(SO4)3(aq) → ZnSO4(aq) Cu(s) b) after completing the experiment, it was discovered that only 10.5 g of copper was made. What is the percent yield.
CHM1025 WS09 Q3c
zhlédnutí 24Před dnem
For each of the following unbalanced equations, suppose exactly 10.0g of each reactant is taken. Determine which reactant is limiting and determine how much of the excess reactant is remaining. c) Na2B4O7(s) H3PO4(aq) H2O(l) → H3BO3(s) Na3PO4(aq)
CHM1025 WS09 Q2a
zhlédnutí 4Před dnem
For each of the following unbalanced equations, calculate how many grams of every product would be produced by a complete reaction of 25.0g of the reactant indicated in bold face (the other reactant is in excess). a) CuCl3(aq) AgNO3(aq) → AgCl(s) Cu(NO3)3(aq)
CHM1025 WS09 Q1a
zhlédnutí 6Před dnem
For each of the following balanced equations, calculate how many grams of every product would be produced by a complete reaction of 15.0g of the reactant indicated in bold face (the other reactant is in excess). a) 2B(s) 6HCl(g) → 2BCl3(s) 3H2(g)
CHM1025 WS09 Q3a
zhlédnutí 13Před dnem
For each of the following unbalanced equations, suppose exactly 10.0g of each reactant is taken. Determine which reactant is limiting and determine how much of the excess reactant is remaining. a) Si(l) CO(g) → SiO2(s) C(s)
CHM1025 WS08 Q6e
zhlédnutí 8Před dnem
Calculate the number of moles of the following e) 1.641 lb of magnesium chloride
CHM1025 WS08 Q6c
zhlédnutí 31Před dnem
Calculate the number of moles of the following c) 56.23μg of silver nitrate
CHM1025 WS08 Q5d
zhlédnutí 6Před dnem
Write the formula and calculate the molar mass of the following d) copper (II) sulfate
CHM1025 WS08 Q5c
zhlédnutí 16Před dnem
Write the formula and calculate the molar mass of the following c) iron (III) nitrate
In 2018, Desiree Linden of San Diego won the Boston marathon
zhlédnutí 14Před 21 dnem
In 2018, Desiree Linden of San Diego won the Boston marathon (42.195km) with a time of 2 hours 19 minutes and 59 seconds (current course record). What was her average speed in mph?
CHM1025 WS05 Q11
zhlédnutí 58Před 28 dny
Write the formula for each of the following binary compounds of nonmetallic elements.
Use the following data to calculate the standard heat of formation, ΔH°f , of manganese(IV) oxide
zhlédnutí 14Před měsícem
Use the following data to calculate the standard heat of formation, ΔH°f , of manganese(IV) oxide
When 1.00 g of solid NH4Cl is dissolved in 25.00 g of water contained in a coffee cup calorimeter,
zhlédnutí 18Před měsícem
When 1.00 g of solid NH4Cl is dissolved in 25.00 g of water contained in a coffee cup calorimeter,
Calculate the frequency of a photon absorbed when the hydrogen atom undergoes a transition
zhlédnutí 21Před měsícem
Calculate the frequency of a photon absorbed when the hydrogen atom undergoes a transition
Given the following reaction:SiCl4(g) + 2Mg(s) → 2MgCl2(s) + Si(s) ΔH = -625.6 kJ
zhlédnutí 33Před měsícem
Given the following reaction:SiCl4(g) 2Mg(s) → 2MgCl2(s) Si(s) ΔH = -625.6 kJ
You are a star🫶🏾
thanks unc
thanks unc
so the 66.4 is the enthalpy change
❤
❤🎉
hello my friend because you're in chemistry I would like to know is there any way to make transparent starch solution? because I tried to filter it and it doesn't work .thx
Maltose might suit you. It is a starch and id does form a transparent solution but it will likely be a yellow color.
shouldn't the temperature be in Kelvin?
Since the equation uses a change in temperature (Tfinal - Tinitial) the units for temperature can be either Kelvin or Celsius.
YAS GIRLIE!! YOU TELL EM!!
Good job 😊
yessss mark taylor tear it up
Your voice wasn't clear so i had to use subtitles but all and all good vid might be short still its good❤
Bro explained it better than my prof(im in 9th grade btw)
Hi where do you take this exercise from? Is it a book? If that’s the case, What’s the name of it?
HI, where do you get your questions from?
hold on a sec, this reaction has a positive Gibbs free energy?
This video shows the calculation for the Enthalpy for the reaction, but the Gibbs energy is actually positive for this reaction (~102kJ)
Great video! Thank you
How do you know how to disperse the electrons like since the total came out to 13 due to the positive charge like you only shared up to the last two boxes and you didn’t disperse 1 into each last 3 idk I’m very confused
Helpful. Thank you
I don't know why I got this as recommended, But good job man 🙌
I just found this channel and I love it. Keep on going!
Pls continue this.
Hi bro
What textbook is this from?
would there be any difference between calculating with excess oxygen or excess hydrogen?
Not interesting
Not interesting
Thanks man really helpful
I wasn't understanding why I was doing it wrong towards the end and you saved me, thank you!:)
Thank you Mark Taylor
I liked this video
Monkey butts
Why did you put the lower concentration in the numerator? Is it because the smaller the concentration the more likely it will be oxidized?
thank you for this video!
Bless 🙌
where are you from dear
umm excuse me, how did you get 9 and 25? Where did those numbers come from!
3^2 and 5^2
WOOO!! GO MR TAYLOR!
why is it 2 e- under Cu?
The copper (Cu) comes from copper sulfate (CuSO4). Since the charge of the copper in copper sulfate is positive two we know the half reaction is: Cu(s) --> Cu^2+(aq) + 2e^-
thank you. I got a 70 on exam 2 and reviewing your videos is filling in the blanks for me, and ultimately preventing me from failing further.
Sorry but do u have any other trick i m indian student preparing for NEET DO U KNOW ABOUT IT
Just came across... Formula of Zinc Acetate.
how did n=5 turn into 9 and n= 3 turn to 25?
3^2 = 9 5^2 = 25
Thank you so much
Thank you SO MUCH for this video! I used this video to review for a quiz retake for my college chemistry class, and I felt WAY more confident about my answer after watching this video than I did on my first quiz attempt having NOT watched the video. Will definitely recommend this channel to my other classmates! ❤️
THANK YOU
can you do a tutorial to dissolve casein in water?
I have never tried but it seems like casein would insoluble in water. Did you want to see a suspension (colloid like) or a significant adjustment of pH (not sure if that would work).
Thank you so much, I hope all of your dreams come true!
Thank you so much.
Life saver
can you explain how you got 1/3 and -1/2
Those fractions are created by taking the inverse of the coefficients from the balance equation.