Video

int a,b,temp; { printf("enter the a number "); scanf("%d",&a); printf("enter the b number "); scanf("%d",&b); temp=a; a=b; b=temp; printf("a: %d,b: %d", a ,b); } result: enter the a number 85 enter the b number 96 a: 96, b: 85

int main() { float length,width,area; { printf("enter the length number "); scanf("%f", &length); printf("enter the width number "); scanf("%f", &width); area=length*width; printf("the area of rectangle %f ",area ); } result enter the length number 10 enter the width number 2 the area of rectangle 20.000000

float n1,n2,add,div; { printf("enter the n1 number "); scanf("%f", &n1); printf("enter the n2 number "); scanf("%f", &n2); add=n1+n2; div=(n1/n2); printf("the add %f ",add ); printf("the result %f", div); }

It is very useful bro video thanks

In 2025 which will be in demand java full stack or python full stack or mern stack( node js)?

Bro ryzen 3000thousand 300hundred series processor irukku but 8gb ram 512gb storage android application run panna mudiyuma

#include <stdio.h> int main(void) { int num1,num2,num3; printf("enter three numbers "); scanf("%d%d%d",&num1,&num2,&num3); if (num1>num3) { printf("the greatest number is %d",num1); } else { printf("the greatest number is ,%d",num3); } if (num2>num3) { printf("the greatest number is ,%d",num2); } else { printf("the greatest number is ,%d",num3); } return 0; } correct ha sir

List out all the language to complete the full stack course bro

Very impressive BRO... Really I took 2 whole years to understand what you said in this 26 mins video... Very thank you for this... 😊

Daily tips... Great idea !!! Passion video link czcams.com/video/ukM1qqlgEVo/video.html

Vs code ❤

Nice❤🎉

Anna enaku childhood la iruthu fighting ta romba pidikum but problem enna na ellam fights pidikum boxing,kartae,judo etc etc so ithu la en Passion eppudi na find pandrthu also Enaku ippa dressing laum intrest athigam so nalla clear idea kudunga✨🙌❤️

We need data base video bro

anna please please angular video upload panunga

My gurunatha one day la 5 video pathean❤ love u bro

Ada paavi neth dhaane medical coding mudiche😢

Thank you so much

All the best bro

Coding padikka English therinjikkanuma anna

Clear explain bro thank you 🎉

bro its vety useful each and every program am practice and i got the output....I watched many more vedios before this vedio..but this is the best vedio..thanks a lott

❤

Iam interested

Swapping without using temp { int a, b, d; Printf("enter a 2 value"); scanf("%d%d", &a&b); d=a; a=b; b=d; printf("a:%d b:%d", a, b); return EXIT_SUCCESS;} Output: Enter a 2 value 5 8 a:8 b:5

Universal tag use pannlam bro

Thank you so much sir.. Love you sir....

Anna neega pesara thu yannku romba pudikum onngaluku agga tha na entha channel la subscribe panni vachi eruka neega ennum neriya vedio upload pannuga nee ga soluudraga romba easy yannku purium.... All the best anna

Kandipa varuma

I am . Diploma 2014 batch arrears also I am learn to Full stock developer course complete ofter job possible or not.. pls explain

Bro I have career gap like 8 yrs , can I continue to learn full stack developer in JavaScript

Nice sir thank you

Vs code

1:05:28

thank you bro

Thank you bro

i don't much about coding but i research it about and vs code can be also used in offline for beginners but google idx is online and yes we needed net for test in vs code but opening and typing doesn't require net, in idx of course u needed net

Freshers devops choose pannalama brother🤔

Vs code

Vs code

Bro entha course mudicha IT field ku ulla poga mudiyum

#include <stdio.h> #include <stdlib.h> int main (void){ setbuf(stdout,NULL); int amount,note500,note100,note50,note20,note10,note5,note2,note1,amount1,amount2,amount3,amount4,amount5,amount6; printf("enter the amount"); scanf("%d",&amount,&note500,&note100,&note50,&note20,&note10,&note5,&note2,&note1); if(amount>=500){ note500=amount/500; amount1=amount-note500*500; } if(amount>=100){ note100=amount1/100; amount2=amount1-note100*100; } if(amount>=50){ note50=amount2/50; amount3=amount2-note50*50; } if(amount>=10){ note10=amount3/10; amount4=amount3-note10*10; } if(amount>=5){ note5=amount4/5; amount5=amount4-note5*5; } if(amount>=2){ note2=amount5/2; amount6=amount5-note2*2; } if(amount>=1){ note1=amount6/1; } printf("the total number of amounts is: "); printf("note500=%d ",note500); printf("note100=%d ",note100); printf("note50=%d ",note50); printf("note10=%d ",note10); printf("note5=%d ",note5); printf("note2=%d ",note2); printf("note1=%d ",note1); return EXIT_SUCCESS; }

Vs code only 😎