Video

😢relatable

Didn't understand the last one but I'm impressed I understood the others! Thank you!

#kenziemadison

Apply - codingblocks.com/careerbootcamp-professionals.html

Thanks for the video. As a contribution, P is subset of intersection of NP and co-NP. Intersection of NP and co-NP is not equal to P as far as we know. For example RSA problem, we know that it is both NP and co-NP but we don't have polynomial time algorithm to solve it.

Personal kyo hore ho

Sir Saturday ka 3rd question bata do

Agar wo sath hain tho sabh kuch ho sakta hain

Kyu kartik bhaiya aur monu bhaiya me ladai karwa cahate ho 😰

bhai audio quality thodi thik karo kuch zyada hi kam hai

Every new admission

I get hi twice. why??

😅😅 right, bi

👾

entry badiya thi waise

what about Pakistan?

thanks

kuch samaj nahi aaya bhut complex way me samjhaya h😢

agguva meeting

bro needs to hesi......aaaaaaaaa......ummmmmmm.......tate less.

Great!!

Q4 solution appears to be O(n*2) but it is still getting accepted in leetcode?

What😂

😂😂😂

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Java ka hai kya

C++

When for java?

#c++

#c++

Awesome Explanation

Itna sach nhi bolna tha 😢

Relatable, Going to send it to my Project Manager 😂

is monu bhaiya's live dsa july batch isnt available on website ??.. pls help if the batch is launched want to enroll for it

how to get layout like you in leetcode IDE

Hey

But Maine toh Java mein kr liya hai, abb kya kru

Aise hi duo me shorts badiya lag rahi hai 😂

When is the next web development batch starting?

good explanation

temp dis samj nahi aaya

NICE SUPER EXCELLENT MOTIVATED

this guy is such a gem 💎 loved it

define int as long long is so much wrong. I have no idea why this is promoted so much, how does this not invoke ambiguity to the compiler? Please clarify.

sir Brute force is work class Solution { public int maxProfitAssignment(int[] difficulty, int[] profit, int[] worker) { // int j = 0; int res = 0; List<Integer> arr = new ArrayList<>(); for (int i = 0; i < worker.length; i++) { int pro = 0; for (int j = 0; j < difficulty.length; j++) { if (worker[i] >= difficulty[j]) { pro = Math.max(pro, profit[j]); } } arr.add(pro); } for(int i=0;i<arr.size();i++){ res += arr.get(i); } return res; } }

Great approach

Thankssssssssssssssss

What is IPO?

Is there any dsa couple taught by monu sir is available live if yes please share links