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Vijay Singh
Registrace 23. 11. 2007
Video
Section15.5: Indefinite Integrals: MATH 158
zhlédnutí 156Před 2 lety
Section15.5: Indefinite Integrals: MATH 158
Section15.5: Indefinite Integrals: MATH 158
zhlédnutí 121Před 2 lety
Section15.5: Indefinite Integrals: MATH 158
Lecture 4: Computing Definite Integral: MATH 158
zhlédnutí 190Před 2 lety
Lecture 4: Computing Definite Integral: MATH 158
Section 10.4 Area between curves Polar Coordinates: MATH 152
zhlédnutí 1,4KPřed 3 lety
Section 10.4 Area between curves Polar Coordinates: MATH 152
Rough Sketch: MATH151, Parametric and Polar Coordinates
zhlédnutí 363Před 3 lety
Rough Sketch: MATH151, Parametric and Polar Coordinates
🌸 promo sm
Waaoooo excellent
Thankuu sir
woww very nice! 🔥🔥🔥
are the solutions 6,51,123?
Great explanation ❤
24:19 sound issues
great help!
Sound issues at 1:50
Video is broken at 33min
hi! thanks for the video! I want to ask what if (p_i) | phi(n). what will be the consequences?
if p divides phi(n), and p>2, then p^k divides n for some k>1.
can you provide these slides
it will se easier to look out for
@@MANISHKUMAR-ut6fp Sure. Drop me your email
Really helpful video. Thank you sir.
thank you sir
wonderful
How find phi(24) ?
One of the consequence of definition of phi function is phi(mn)=phi(m)phi(n) and phi(p^k)=p^k-p^(k-1). Now, phi(24)=phi(3x8)=phi(3)×phi(8)=2×4=8. Alternatively, since 24 is a "small" number, find all the numbers less than 24 and co-prime to 24. There are exactly 8 of those: 1, 5, 7, 11, 13, 17, 19, 23.
it is not 4 mod 8, it should be 4 mod 2. because 2 doesn't need to multiply to 4
Can you explain again why there are no solutions to phi(theta)= 3 ? you said because phi(x) is even so only odd number allowed is 1. Is that a theorem or ?
Theta is a natural number, so it can be written as product of powers of prime. If p is prime divisor of theta, then p-1 divides phi(theta). But p-1 is even for any prime except 2, therefore, theta cannot have any prime factors other than 2. Now if theta is power of 2, say 2^k, then phi(2^k)=2^{k-1}. So, k cannot be greater than 1 to have an phi(theta)= odd number. However, if k=1, then you have phi(theta)=1. Therefore, the result.
Thanksss
I like your ringtone
when you wrote down the expression of u_2 prime what is g1? We've never defined what is g1 anywhere. Is it different from the g on the RHS in the general form of the second order DE? Time stamp: 18:10
4:48 how to interpret the chain rule over there?
Audio: 39:06 40:56
8:30 classic quote
mic problem time stamp 0:17 1:51
the volume up was one way to wake up XD 9:55
I didn't read the comment first and I almost had a heart attack
shouldn't the interval of convergence @ 14:06 be (-2, 6] instead of (2, 6]? Since we got -2 < x < 6 and we needed to check what happens at x = -2 and x = 6?
You are correct. It should be (-2,6]. I made an error in copying down from above.
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You made an error in -(x-1)...it should be 1-x implying x=1.
-a=0 implies a=0, so it is correct. I believe you are talking about t=29.27 min?
12:25 it should be q*y2
Quadratic equation at 27:34 should be 16r^2-8r+145 right? Not 16r^2-8r+15
yes, it was corrected in the class. Thanks!
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Will you be doing the missing part in class this semester?
Yes. In the next class.
Thanks, Subscribed <3
Thank you
0:50 hotsisters.online
First Viewer
First!
Great vid!
Hi, I cannot see anything from 33:22
I cannot see it either. My bad. I will do that part in the class\office hours today.
@@vks1231 Would you be able to upload it only for that part please? Note is ok for me
Thanks for the good audio quality
warning @ 16:09, 18:15, 19:26, 21:13 and 24:24 :))
Thanks JP, I do not know what happened with the audios at those times.
thanks man these timestamps rebuilt my entire image of mathematics
Thanks for the warnings, I get frightened easily :(
the audio