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Y/X = 6 Y = 6X Y = 10a + b a + b = X Y = 9a + a + b = 9a + X 9a + X = 6X 9a = 5X 9a/5 = X later i finish it im late

So oo <- infinity is any number from -oo to oo, so why not just show [ -oo; oo ]

Giving new meaning to "junk science."

Some of the things on that list were less surprising because they kind of math the same, but other things on that list were mind bananas. Something for everyone. I totally dig this guy's math videos. They're nutrient dense and very enthusiastic.

Of course you do.

Wait... wouldn't that just be +infinity and -infinity added together so that would be x+-x=0 x÷0=0

Did you know that 1 / 0 = pi

We use it for a random number generator in programming computers.

2 shoulda bee in there with the units, pi. e, and phi. In terms of integers, going up from 0 you really don't see a downward turn in "interestingness" until 3, which is less interesting then 2, fight me.

What about 14159?

If Pi does contain every random string of numbers, it would be known as a "normal number"

call me stupid all y'all want but can't you just say that the answer is ± infinity?

Dj is a word. Its not an acronym anymore seeing as bei g a disc jocky isnt the only way in which you can be a Dj

I like your clocks man where are your manetes?

No words end in this combo: dncivnebdjvnnwidjebqb

I realized the same thing as a kid. I concluded that positive and negative infinity were the same thing and thought if you go infinitely into debt you actually become rich.

A distinction without a difference

Why did you have to make that more complicated than it had to be. Stop smoking crack dude😂 just cuz you sound like you know something, doesn’t mean you actually know anything 😂

Imma just write huge numbers with 0s all around to practice

Damn Bill Nye’s son has lost it

Nerd understand nerd 🤓🤓🤓

Infinite number of digits, not infinite amount of digits.

I asked chat gpt: In standard arithmetic, \(1 + 1 = 2\). However, in some alternative number systems or contexts: - In base-3 (ternary) system, \(1 + 1 = 2\), because base-3 digits are 0, 1, and 2. - In base-2 (binary) system, \(1 + 1 = 10\), where the digits are 0 and 1, and adding 1 and 1 results in a binary carry-over. So, \(1 + 1 = 3\) is not correct in typical number systems, but \(1 + 1 = 10\) is correct in binary.

Your good at math: 😊 Your memory: 💀 ELA: 💀

So it's a fallacy.

Like a shift register

Well done!

Thought tahr was a Cigarett.

😮😮

I truly expected this video to jave like 4 Million likes or sumtn, the algorithm will favor this humorous and informative content

6 is when the valedictorian is also the class president and the star track runner and the lead in the school musical and took the soccer team to state finals and won the top prize at a national science fair and made friends with the kid everyone else made fun of and got a scholarship to Harvard

It's scientific notation!

This guy is uneducated.

The matrix has been unlocked

The monkey in the forest watching him be like: 🤨

when the target of multiplication is an integer i call it adding a zero to the end but if it is a decimal number i call it moving the decimal.

I show up for these videos equally to learn math stuff and to find out what's going to break or fall down.

But Terrance Howard told me the cubed root of two is just two times the root of two which means one times one is two. So there is that.

in a state of entropy how could a proto-chicken hatch a chicken with more information than the parent proto-chicken?

does this work in exotic bases? empirically it seems to, at least for negative, noninteger, and fractional ones whose magnitude is greater than 1 is there a good proof that works for such bases? I can't test empirically for bases less than 1, but if you do the fancy tricks for getting a value for diverging infinite sums does it work on those?

Sir, i don't get it please explain me what do you mean by "will require less amount of zeroes"

Prompt ends in mt

Thats a cool way to think about it I always went with the second idea

That’s how I thought of it, too! Nice to hear it’s not uncommon.

Also make sure to check out my latest episode on my main @ComboClass channel about equations that are true in multiple bases: czcams.com/video/wwZBwiHUT6Q/video.html

Just saying, that's yet another of the countless proofs that 0.9999... = 1 : if 0.111111.... is 1/(b-1) where b is the base we're counting in, if you moltiply for b-1 both sides you get on one 0. The last digit of the system repeating infinitely, and on the other side you have 1. In the case of base 10, that gets precisely 0.9999.... = 1, but it can be generalised in any base (in base 2 you have 0.11111...=1, in base 3 you get 0.22222...=1, and so on)

once again descartes proved to be a bitch and a buster

Ω

Hadj

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