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Magic Masala Maths | Jensen's Inequality | Derivation of AM-GM, RMS-Avg Inequality | Theory | 012
Problem statement:
Prove the Jensen's Inequailty
Derive the Arithmetic mean and geometric mean inequality (AM GM inequality)
Derive the Root mean square and Average inequality (RMS Avg inequality)
0:00 Jensen's inequality
0:59 RMS-Avg inequality
1:30 AM GM inequality
🚀 Boost Your Enthusiasm for mathematics and Olympiads!
Hi there, this is Markosa, and I love making math enjoyable and accessible for everyone. Whether you're preparing for JEE, IMO, USAMO or just love math, this quick solution will help sharpen your problem-solving skills. Join me as we explore the beauty of math together-because math can be fun and educational!
✨ Why Watch?
Learn easy derivation of inequalities.
Improve your math skills with concise explanations.
Enjoy math for fun and learning.
🔗 Subscribe for more quick math solutions and problem-solving tips!
Tags:
#JEEAdvanced #MathWithMarkosa #imo #matholympiadproblem #ProblemSolving #MathLover #USAMO #IITJEE #QuickMath #JEEStrategy #Education #FunWithMath#education #mathematics #olympiad #problemsolving #jeeadvanced #jee #iitjee #functions #cauchy #schwarz #inequality #usamo
Prove the Jensen's Inequailty
Derive the Arithmetic mean and geometric mean inequality (AM GM inequality)
Derive the Root mean square and Average inequality (RMS Avg inequality)
0:00 Jensen's inequality
0:59 RMS-Avg inequality
1:30 AM GM inequality
🚀 Boost Your Enthusiasm for mathematics and Olympiads!
Hi there, this is Markosa, and I love making math enjoyable and accessible for everyone. Whether you're preparing for JEE, IMO, USAMO or just love math, this quick solution will help sharpen your problem-solving skills. Join me as we explore the beauty of math together-because math can be fun and educational!
✨ Why Watch?
Learn easy derivation of inequalities.
Improve your math skills with concise explanations.
Enjoy math for fun and learning.
🔗 Subscribe for more quick math solutions and problem-solving tips!
Tags:
#JEEAdvanced #MathWithMarkosa #imo #matholympiadproblem #ProblemSolving #MathLover #USAMO #IITJEE #QuickMath #JEEStrategy #Education #FunWithMath#education #mathematics #olympiad #problemsolving #jeeadvanced #jee #iitjee #functions #cauchy #schwarz #inequality #usamo
zhlédnutí: 2
Video
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zhlédnutí 9Před 20 hodinami
Problem statement: Prove that if a, b, c are positive real numbers then \[ a^ab^bc^c \ge (abc)^{(a b c)/3}.\] 0:00 Problem description 0:05 Solution 🚀 Boost Your Enthusiasm for mathematics and Olympiads! Hi there, this is Markosa, and I love making math enjoyable and accessible for everyone. In this video, I take on a challenging problem from USAMO 1984 and solve it in just 2 minutes! Whether y...
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zhlédnutí 38Před 4 hodinami
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zhlédnutí 9Před 7 hodinami
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zhlédnutí 7Před 12 hodinami
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zhlédnutí 15Před 14 hodinami
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zhlédnutí 16Před 16 hodinami
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zhlédnutí 18Před 16 hodinami
Try to solve this problem. A line y = mx 1 intersects the circle (x - 3)2 (y 2)2 = 25 at the points P and Q. If the midpoint of the line segment PQ has x =3/5, then which one of the following options is correct? 0:00 Problem description 0:04 Solution 🚀 Boost Your JEE Advanced Preparation! Hi there, I'm Markosa, and I love making math enjoyable and accessible for everyone. In this video, I take ...
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zhlédnutí 11Před 19 hodinami
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zhlédnutí 4Před dnem
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zhlédnutí 12Před dnem
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zhlédnutí 48Před rokem
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Very nice 😊
Just take sqare on both sides and √2x -1 - √2x - 1 + x + x = 2 So 2x = 2 X = 1 😑
Amazing... Loved it!!