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Simple Civil
Canada
Registrace 17. 04. 2020
Hey, Welcome to the Channel!
The goal here at Simple Civil is to create easy to follow education videos related to a wide range of topics in the civil engineering field. The information is curated from my student experience and conveyed in a way to efficiently teach concepts and complex numerical problems. All playlists are organized based on typical school curriculum and will contain questions for each section.
The channel will grow overtime and have playlists ranging from Strengths of Materials, Soils, and Differential equations to start with. So feel free to subscribe and stay up to date on the upcoming content!
Learning for students, by students!
The goal here at Simple Civil is to create easy to follow education videos related to a wide range of topics in the civil engineering field. The information is curated from my student experience and conveyed in a way to efficiently teach concepts and complex numerical problems. All playlists are organized based on typical school curriculum and will contain questions for each section.
The channel will grow overtime and have playlists ranging from Strengths of Materials, Soils, and Differential equations to start with. So feel free to subscribe and stay up to date on the upcoming content!
Learning for students, by students!
Moment Resistance for Unique Concrete Beams!
Hi guys! I hope you find this video helpful! I plan to slowly introduce the concepts of concrete design on this channel based on CSA A23.3. We cover moment resistance and design assumptions in this video. The following question is covered.
A concrete beam with an irregular cross section has 100 mm x 100 mm notches at the corners within the compression zone. Assuming the beam is properly reinforced, Determine the factored moment resistance (Mr) with the given material properties:
( fy ) = 400 MPa.
( fc' ) = 30 MPa.
( Փc ) = 0.65.
( Փs ) = 0.85.
If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
DISCLAIMER: All referenced code clauses and information extracted from the code clauses in this video have been confirmed to be publicly available information subject to free use.
A concrete beam with an irregular cross section has 100 mm x 100 mm notches at the corners within the compression zone. Assuming the beam is properly reinforced, Determine the factored moment resistance (Mr) with the given material properties:
( fy ) = 400 MPa.
( fc' ) = 30 MPa.
( Փc ) = 0.65.
( Փs ) = 0.85.
If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
DISCLAIMER: All referenced code clauses and information extracted from the code clauses in this video have been confirmed to be publicly available information subject to free use.
zhlédnutí: 85
Video
Solve Moment Resistance for Concrete Beams!
zhlédnutí 90Před 21 dnem
Hi guys! I hope you find this video helpful! I plan to slowly introduce the concepts of concrete design on this channel based on CSA A23.3. We cover moment resistance and design assumptions in this video. The following question is covered. A concrete beam is properly reinforced with 2-25M bars in the tension zone. Determine the factored moment resistance (Mr) of the beam. If you have any recomm...
Intro to Flexural Concrete Member Design!
zhlédnutí 58Před měsícem
Hi guys! I hope you find this video helpful! I plan to slowly introduce the concepts of concrete design on this channel based on CSA A23.3. We cover specified effective depth, area of steel reinforcement, reinforcement ratio, concrete cover, and rebar spacing in this video. The following question is covered. A simply supported reinforced concrete beam has the following cross section as shown. T...
Intro to Reinforced Concrete Design for Beginners!
zhlédnutí 111Před měsícem
Hi guys! I hope you find this video helpful! I plan to slowly introduce the concepts of concrete design on this channel based on CSA A23.3. We cover specified compressive strength, modulus of rupture, and modulus of elasticity in this video. The following question is covered. A simply supported unreinforced concrete test beam spanning 2.4 m fails under the following loaded configuration as show...
Built Up Columns and Critical Buckling Load!
zhlédnutí 84Před 2 měsíci
Question 13-9: A column is constructed using four A992 steel angles that are laced together as shown. The length of the column is to be 25 ft and the ends are pin connected. Each angle shown below has an area of A = 2.75 in2 and moments of inertia of Ix ' = Iy ' = 2.22 in4. Determine the distance d between the centroids C of the angles so that the column can support an axial load of P = 350 kip...
Column Buckling and Lateral Bracing Problem!
zhlédnutí 255Před 3 měsíci
Question F13-3: The A992 steel column can be considered pinned at its top and bottom and braced against its weak axis at the mid-height. Determine the maximum allowable force P that the column can support without buckling. Apply a F.S. = 2 against buckling. Ix = 87.3(10-6)m4, and Iy = 18.8(10-6)m4 If you have any recommendations for future problems, or have suggestion for tutorials in the futur...
Intro to Column Analysis and Critical Axial Loads!
zhlédnutí 118Před 3 měsíci
Question 13-31: The steel bar AB has a rectangular cross section. If it is pin connected at its ends, determine the max allowable intensity w of the distributed load that can be applied to BC without causing bar AB to buckle. Use a FS with respect to buckling of 1.5. Est = 200 GPa, Ϭy = 360 Mpa. If you have any recommendations for future problems, or have suggestion for tutorials in the future,...
Easy Superposition Deflection Problem!
zhlédnutí 111Před 4 měsíci
Question 12-87: The W12 x 46 simply supported beam is made of A-36 steel and is subject to the loading shown. Determine the deflection at its center C. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
Intro to Slope and Deflection by Superposition!
zhlédnutí 128Před 4 měsíci
Question *12-84: The W 10 x 15 cantilevered beam is made of A-36 steel and is subjected to the loading shown. Find the displacement at B and the slope at B. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
Solving Slope and Deflection by Integration!
zhlédnutí 222Před 5 měsíci
Question *10-32: Determine the equations of the elastic curve using the x1 and x2 coordinates, and specify the slope at A and the deflection at C. EI is constant. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
Slope and Deflection by Integration Problems made Easy !
zhlédnutí 96Před 5 měsíci
Question *10-32: Determine the elastic curve for the cantilevered beam W14 x 30 using the x coordinate. Specify the maximum slope and maximum deflection. E = 29(10^3) ksi. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
Moment Area Theory made Easy (Part 2)!
zhlédnutí 73Před 6 měsíci
Question: Apply both Moment Area Theorems to determine the slope and deflection at point C of the beam shown. 'I' varies throughout the member! Hey everybody! If you found this video helpful, feel free to leave a like. Any support helps and lets me know these videos have helped! If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to lea...
Moment Area Theory made Easy (Part 1)!
zhlédnutí 80Před 6 měsíci
Question: Apply both Moment Area Theorems to determine the slope and deflection at point C of the beam shown. 'I' varies throughout the member! Hey everybody! If you found this video helpful, feel free to leave a like. Any support helps and lets me know these videos have helped! If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to lea...
Easily Solve Compound Stress Problems!
zhlédnutí 115Před 7 měsíci
Question *7-189: A short post supports a vertical force P = 9600 lb and a horizontal force H = 800 lb. Determine the vertical normal stresses at corners A, B, C, and D of the post. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
Composite Beams using Transform Area Method!
zhlédnutí 495Před 7 měsíci
Question 6-130: The beam is made from three types of plastic that are identified and have the moduli of elasticity shown in the figure. Determine the maximum bending stress in the PVC. If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!
The Basics of Transform Section Method for Composite Beams!
zhlédnutí 596Před 7 měsíci
The Basics of Transform Section Method for Composite Beams!
Using the Flexure Formula given an Allowable Bending Stress!
zhlédnutí 590Před 8 měsíci
Using the Flexure Formula given an Allowable Bending Stress!
The Basics for using the Flexure Formula!
zhlédnutí 337Před 8 měsíci
The Basics for using the Flexure Formula!
Understanding the Flexure Formula with Examples!
zhlédnutí 197Před 8 měsíci
Understanding the Flexure Formula with Examples!
Solving Thin Wall Closed Tubes Problems!
zhlédnutí 178Před 9 měsíci
Solving Thin Wall Closed Tubes Problems!
Torque Problems with Non-Circular Solid Shafts!
zhlédnutí 193Před 9 měsíci
Torque Problems with Non-Circular Solid Shafts!
Visualizing the Gear Ratio for Indeterminate Torque Loaded Assemblies!
zhlédnutí 1,5KPřed 9 měsíci
Visualizing the Gear Ratio for Indeterminate Torque Loaded Assemblies!
Understanding the Gear Ratio and Torque!
zhlédnutí 841Před 9 měsíci
Understanding the Gear Ratio and Torque!
Solving for Torque in Composite Indeterminate Shafts!
zhlédnutí 1,2KPřed 10 měsíci
Solving for Torque in Composite Indeterminate Shafts!
Indeterminate Torque Loaded Member Theory and Examples!
zhlédnutí 340Před 10 měsíci
Indeterminate Torque Loaded Member Theory and Examples!
Solving Statically Determinate & Indeterminate Frames!
zhlédnutí 1,8KPřed rokem
Solving Statically Determinate & Indeterminate Frames!
Solving Statically Determinate & Indeterminate Trusses!
zhlédnutí 1,3KPřed rokem
Solving Statically Determinate & Indeterminate Trusses!
In shape 4, while solving for the X Tilda, why did you have to add one third of the triangle base instead of half??
Good question! For the given triangle, the centroid is not exactly at 1/2. If you search up 'right triangle centroid' in google images, you will see that we need to move 1/3 from the left of the triangle to reach its centroid. Hope this helps.
@@simple_civil yeah it does thanks. I really enjoyed your class,thumbs up man.
@@edwinanthony2383 Glad I could help my friend
Problem begins at 7:58. Hope this video was a good introduction to basics of concrete design! If you have any questions, let me know.
Please note, b = 600 mm ! If you have any questions, feel free to ask! Thanks for watching
Note: The a1 = B1*c should be a = B1*c. Sorry about that! Problem begins at 9:53. Thanks for watching and supporting!
Lol, getting to learn this is ninth grade, for Indian exams... very well taught! But I'd say our questions are more trickier, that's why cant afford to watch this 🤣
Haha, Parallel axis theorem definitely gets harder with exams! But as long as you have strong fundamentals, you can solve any problem! Thanks for watching
Just found the channel, and i find the content extremely useful and well done!
Thank you so much! I appreciate the support
Problem begins at 8:59. As always, thanks for watching and supporting. Leave any questions in the comments below!
Can you give a real life example where you would need to consider where an angular plane needs to be considered and stress at that plane with respect to axial load needs to be calculated?
An example that comes to the top of my head would be having an an axially loaded member, fastened together in the middle by a bolted connection, but the connection between the two members is at an angle instead of perfectly perpendicular to the load. I'm sure there are more examples in textbooks, but I also assume that the most likely used for these formulas would be for material testing purposes. Hope this helps!
If you are using the 45, 45, 90-degree triangle, how can you have two legs that are equal to length 2, and a hypotenuse that also has a length of 2 while maintaining a 90-degree angle? It simply goes against the trig ratios of the unit triangle.
Bit confused by this. The hypotenuse length is not really relevant to the problem and the dimension of the hypotenuse is not mentioned explicitly. Sorry!
Awesome Overview of the concepts man!! Helps really understanding the basics. Keep Making this Videos.
Thanks for the support, I really appreciate it!
what for Iy
Give it a try! It is a similar procedure, just now use the y axis as your reference axis!
@@simple_civil I did got like 10.3x10^9
perfect
Glad I could help!
@@simple_civil the evaluation was today, i think the mass geometry exercice, from the mechanical engineering mechanics I course is full correct. Thank you a lot
@@GB-eq4db That is amazing! Glad I could be there to help!
Thank you very much, greetings from Turkey
Thanks for the support, love from Canada!
Hey y'all thanks for watching! My mouse is not showing unfortunately at the start so I do apologize for that. Hope this helped and thanks for the support.
If you have a concrete slab on top of a steel beam which one do you transform
You can do either, but typically you convert the concrete to steel. It is much easier as the slab is a simple rectangle, while the beam has multiple individual rectangular sections. Additionally, for analysis, you would take the tributary area of that slab above the beam, and use that as your untransformed b value. hope that helps!
Which device ur using to record this video.?
Thanks! I use OBS for my recordings, it is a free software
Nice work!
This is a fantastic video, thanks. How would you solve the same problem, but with the distributed force triangle being highest at x = 0 rather than at x = 9ft? Seems to me that you'd have to use the segment from the right, rather than the left - but I feel like there must be a simpler/quicker way than that.
Nevermind. :) It is actually really just as simple doing it from the right as it is from the left. I just have the roller support as the constant rather than the pin support. (And I just need to keep track of where I'm measuring x from. But I got the right answer, so it works! Thanks!!)
@@sceneryj Haha glad you were able to test both ways. At the end of the day, whatever is intuitive for you, go for it. Glad you enjoyed the video as well
I express my humble gratitude to you sir ! I am also an undergrad student of CE from JADAVPUR UNIVERSITY... Your tutorials helped us a lot in our semester exam. Thank youuuu!! SIR
Wow! I am so glad I was able to help you and your classmates! Thanks again for the support my friend
hi i have a question if we have forces on L and H. would LC and HE be zero force members too? thank you so much for this video.
Hey! thanks for the support by the way. Like I said in the video, it is best to break down a four member joint into a FBD to imagine the reactions taken by each. I believe in the case you are asking for, we would have four y components and three x components in the members cumulatively. So in this case, it is hard to say without analyzing other joints to determine some unknowns in that joint first. Hope this helps!
Thanks for the help!
Glad I could help!
Problem begins at 5:38. Leave a like if this helps, and ask any questions below <3
thanks
Glad I could help !
thank you sir
No problem! Glad I could help my friend
Why is a 3 and not 1.5?
Hey! Its a special triangle (also called a 3 4 5 triangle). You can use 1.5, 2 and 2.5, but its just common to write it as 3 4 5 when you have the equivalent relationship. Hope that helps
Thanks for all the recent support guys! Leave any questions or comments below <3
Problem begins at 2:50. Thanks for watching! Sorry that my cursor is not showing up, will be sure to have that fixed next time! Leave any questions below <3
But I found shear stress to be -3MPa not 53 MPa. Can you please clarify on that
I believe the first part of the equation, you end up with the wrong sign. -(-65-(-125))/2 sin (2 x 145) should give approximately a positive 28.2 and the 75cos (2 x 145) should give approximately 25.6. Hope that helps!
Summing the forces in the Y direction for K. Would Fkd be positive in your first equation instead of negative because the direction of the force is pointed upward?
Hey! I did this video a while ago, but Ill see if I can help. From the FBD (free body diagram) I have, Fkd is drawn in the positive x (pointed to the right with respect to the joint) and the negative y (pointed downward with respect to the joint). So the signs in the equations seem to be right based on what is drawn. Then when Fkd is solved, we end up with a negative value, meaning the Fkd drawing needs to be flipped and pointed towards the joint. Then, based on our convention, we are pushing the joint. Thus, Fkd is a compressive force. Hope this helps!
If this video was helpful, feel free to leave a like! Ask any questions below <3
Can you mention which notes taking app do you use and which tablet ?
This is OneNote and I am using the Wacom One Tablet. Thanks for asking!
Why is Aplane=A/cos(theta)?
Hey! It should be just basic SOH CAH TOA. CAH is cos(theta) = A / A(plane). Rearranging this, we are left with A(plane) = A / cos(theta). Hope that's okay!
I see now. Thank you!@@simple_civil
P=N cos(theeta). Am i correct sir
@@sabugeorge5001 P=N / cos(theta)! Thanks for asking
Just a quick note, w = EI (d4y / dx4). It is to the 3rd power in the video. Apologies!
Problem begins at 8:15. Thanks for watching and supporting!
2:48
The different versions of the pictures make it so much easier to visualize, and your explanations for the components and the moments made it much easier to understand the concept. I'm taking Statics this semester with some basic engineering courses, so anything I can watch, listen and practice with is greatly appreciated. Thank You!
I love reading comments like this! I'm glad I could make things easier to understand. I wish you the best in your courses
Thanks Needed a touchup on the topic
Thanks for watching. Definitely a long solving process!
sir ty
No problem, glad I could help!
i like this channel, if will next very nice
Thanks for the support!
sorry if it sounds dumb but why when you solved in terms of [y] you didnt subtract the curve equation from 2 just like you did for x
No worries! The strips are bounded by the axis and underneath the curve . So for Iy, we are going from 0 to 1, and we don't need to do any 'subtracting of the 2' since the equation already gives us what we are looking for. In other words, our dA is already bounded in the area we are interested in. Then for Ix, it is different. We initially have dA bounded between the curve and the y axis from 0 to 2, which does not represent the area we are integrating. This is why we take 1 - (y / 2 ) ^ 1/4 to get dA where it needs to be. Definitely hard to explain in a comment, but I hope this helps!
@@simple_civil Oh i see now ,Understood thanks a lot man🫡
@@hylexsenpai5282 Glad I could help <3
thanks
No problem, glad I could help!
How can we tell the sign of the moments i.e. for the moment due to F1 when regarding the various axes? I'm trying to use the right hand rule and it just doesn't seem to work out. Could you provide an explanation on how to determine the direction of these moments? Thank you.
Hey! To start, the right hand rule is applicable to our sign conventions here. Our thumb points in the positive direction of our axis, and the moment reactions were both drawn in the positive convention (following our grip around the axis). If we look at only F1, we would have moment reactions about the y and x axis. The support allows no moment reaction to develop on the y axis, and the z axis is parallel to our force, so there will be no moment reaction there either. Now, solving for the moment at x (Max), F1 would create a clockwise moment about that axis. This means our reaction moment will be counterclockwise. This also means our assumption to drawing it this way was correct! Hope this helps!
@@simple_civil Sorry but I'm still not one hundred percent -- if we point our thumb in the direction of the positive y-axis, are our fingers, before curled, the direction of the force (for F1 this would mean that the fingers are pointing down still with the thumb pointing along the positive y-axis and for FBC and FBD are pointing up) and the curling defines the direction? Because if I do that, the curling due to FBC / FBD about the positive y-axis would still be counterclockwise. I appreciate you taking the time to help.
still don’t understand how to get ec
Ill give you a breakdown for each problem: 1) There is no internal hinge in the problem, therefore, we set ec = 0. 2) There is 1 internal hinge. m' is the number of members connected by the hinge. Therefore, we have ec = 4 - 1, which gives us 3. Hope this helps!
one vid, can you go over imperial units of mass and force. whhats the need both for lbm & slug, for example?
Hmm, that would be a good idea for a video! Down the road if I start a Intro to Physics Series I could do some stuff on units.
Thanks for the video but i have a question, how do i calculate the moi about the x axis when the centrodial axis is the axis itself...as in the x and y axis are located in the middle of the shape
Hey there, thanks for the question! Basically, when the axis is given at the centroid (or center), that means we do not need to consider the Ad^2 part (since d will equal 0). The global and local axis aligned. Hope that helps, let me know!
Very helpful, got this in my exam and was trying to figure out how this was done for the longest time, though in metric. Would you get the same answer if you converted everything to Bakelite and then used the transformation factor on on the pvc answer afterwards?
Yes you would! The trick is at the end, when using the flexure formula, you need to use the modular ratio to convert the bakelite back into PVC to get the equivalent stress in the PVC. Love reading comments like this, glad I could help!
life saver thanks for the methode i was struggling with the double integral methode of my book
I'm so happy to hear that! Thanks for watching!
Hope this video helped! Thanks for watching!
Problem begins at 8:32. Once again, thanks for watching and supporting the channel!
Hope this video was helpful for you! If you have any questions, let me know!